5(n-4)=(4n-12)
First: Distribute 5 into n and -4.
5(n-4)=(5n)+(5*-4)= 5n-20.
Second: Subtract 4n from both sides to eliminate the variable from the right side of the equation.
(5n-20)=(4n-12)
n-20=-12
Next: Add 20 to both sides to eliminate the constant from the left side of the equation.
n-20=-12
n=8
The unknown number is 8.
Answer:
Step-by-step explanation:
Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.
The first step of factoring is to try to factor out a common factor.
The terms x^2 and -9x have the factor x in common.
Factor out x from both terms.
x^2 - 9x = 0
x(x - 9) = 0
Now you have a product of fully factored terms equaling zero, so you can apply the zero product property to solve.
x = 0 or x - 9 = 0
x = 0 or x = 9
Answer: x = 0 or x = 9
Use the FOIL method
First, Outside, Inside, Last
(2x -5)(x + 3)
2x(x) = 2x²
2x(3) = 6x
-5(x) = -5x
-5(3) = -15
2x² + 6x - 5x - 15
simplify
2x² + 6x - 5x - 15
2x² + x - 15
2x² + x - 15 is your answer
hope this helps
