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3 years ago

8

a sixth grade class of 12 boys and 24 girls consider this statement for every two boys there are 4 girls do you agree with the s

tatement explain

1 answer:

BaLLatris [955]3 years ago

6 0

Yes it could be simplified to 2 girls every 1 boy but what you have is correct and I agree because if you divide each side by the corresponding number so 24/4 and 12/2 the both equal 6 so I agree

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EASY 100 POINTS PLEASE HELP

mamaluj [8]

Answer:

They are parallel and congruent

Step-by-step explanation:

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2 years ago

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Kyle wants to compare 0.02 to 1/4 using fractions. Which fraction can you use for 0.02?

Crazy boy [7]

Answer:

$\frac{1}{50}$

Step-by-step explanation:

$\text{Kyle wants to compare 0.02 to }\frac{1}{4} \text{ using fractions}\\\\\text{we need to convert 0.02 into fractional form.}\\\\\text{to convert a decimal into fractional form we divide by }10^n,\\\text{where n is the number of digits after decimal, and remove decimals}\\\text{from the number.}\\$

$\text{here in 0.02, we can see that the number of digits ater decimal is 2,}\\\text{so to convert it into fractional form, we get}\\\\0.02=\frac{2}{10^2}\\\\=\frac{2}{100}\\\\=\frac{1}{50}\\\\\text{so in decimal form, we can write 0.02 as }\frac{1}{50}\\$

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3 years ago

Please someone help me with this question

const2013 [10]

Basically something like this

7 0

3 years ago

what are the solution(s) to the quadratic equation 9x2 = 4? x = 4/9 and x = -4/9 x = 4/9 and x = -2/3 x = 3/2 and x = -3/2 no re

Kamila [148]

To solve for the quadratic equation 9x² = 4, we need to recall that the difference between two square can be expressed as the product of their sum and difference or (a² - b²) = (a + b)(a - b). Thus, we have 9x² = 4 9x² - 4 = 0 (3x)² - (2)² = 0 (3x + 2)(3x - 2) = 0 We now have two linear equations: 3x + 2 = 0 | 3x - 2 = 0 3x = -2 | 3x = 2 x = -2/3 | x = 2/3 Thus, x = +2/3 and -2/3.<span> </span>

6 0

4 years ago

Can SOMEBODYYY please do the maths!!! PLeassssssssssssseeeeeeee

Anna11 [10]

Answer:

<h2>see below</h2>

Step-by-step explanation:

<h3>Question-6:</h3>

we are given a equation

$\sf \displaystyle \: \log_{4}( - x) + \log_{4}( 6 - x) = 2$

to solve so

recall logarithm multiplication law:

$\sf \displaystyle \: \log_{4}( - x \times (6 - x)) = 2$

simplify multiplication:

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = 2$

remember $\displaystyle \log_{4}(4^2)=2$

so

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = \log_{4}( {4}^{2} )$

cancel out $\log_4$ from both sides:

$\sf \displaystyle \: - 6 x + {x}^{2} = {4}^{2}$

simplify squares:

$\sf \displaystyle \: - 6 x + {x}^{2} = 16$

move left hand side expression to right hand side and change its sign:

since we are moving left hand side expression to right hand side there'll be only 0 left in the left hand side

$\sf \displaystyle \: - 6 x + {x}^{2} - 16 = 0$

rewrite it to standard form i.e ax²+bx+c=0

$\sf \displaystyle \: {x}^{2} - 6x - 16 = 0$

rewrite -6x as 2x-8x:

$\sf \displaystyle \: {x}^{2} + 2x - 8x - 16 = 0$

factor out x and 8:

$\sf \displaystyle \: x {(x}^{} + 2) - 8(x + 2) = 0$

group:

$\sf \displaystyle \: (x - 8){(x}^{} + 2) = 0$

$\displaystyle \: x = 8 \\ x = - 2$

$\therefore \: x = - 2$

<h3>Question-7:</h3>

move left hand side log to right hand side:

$\displaystyle \: \log(x ) + \log(x - 21) = 2$

use mutilation logarithm rule;

$\displaystyle \: \log( {x}^{2} - 21x) = 2$

$\log(10^2)=2$ so

$\displaystyle \: \log( {x}^{2} - 21x) = \log({10}^{2} )$

cancel out log from both sides:

$\displaystyle \: {x}^{2} - 21x = 100$

make it standard form:

$\displaystyle \: {x}^{2} - 21x - 100= 0$

factor:

$\displaystyle \: {(x} + 4)(x - 25)= 0$

so

$\displaystyle \: x = 25$

5 0

3 years ago