I believe that the ice cube, being that it still has almost all of its properties, would still have a mass of 25 g after melting
Answer:
(CH3)3N(aq)
Explanation:
We have to think of the definition of acid and base in the sense of Brownstead-Lowry. The Brønsted–Lowry theory is an acid–base reaction theory which was proposed independently by Johannes Nicolaus Brønsted and Thomas Martin Lowry in 1923.
A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction. In contrast, a Bronsted-Lowry base accepts hydrogen ions. When it donates its proton, the acid becomes its conjugate base. A more general approach to the theory is viewing an acid as a proton donor and a base as a proton acceptor.
If we look at the reaction closely, we can see that (CH3)3N(aq) accepted a proton. According to the definition above, we will have to classify (CH3)3N(aq) as a base. Hence the answer.
protons and electrons are both always the atomic number which is 9 in this case.
For neutrons you subtract the atomic number (9) from the weight of the atom (18.998) some teachers will want you to round to the nearest whole (19). We do this because the number of protons is the atomic number so if you subtract the protons from the whole weight of the atom you would have the electrons and neutrons left. Since electrons weigh so little we don't have to subtract them. Weighing neutrons and electrons would be like weighing an elephant (neutrons) and then putting one marshmallow on the scale (electron).
Answer: For this homework question, you’ll need to look up the molar mass of AgNO₃. Use this to calculate the number of moles in the sample.
Then note that silver is (quite usually) univalent, so there will be as many moles of AgCl as there were of AgNO₃.
Ask your instructor or tutor for more in-depth training, if need be. Good luck!
Explanation:
The diameter of the pool is 4
Explanation:
To calculate the diameter we must write the values given in the question, here
The circumference of the pool is given as C=12.56 feet.
To calculate the diameter of the pool,
If radius is given, Multiply the radius by 2
If Circumference is given divide the circumference by Pi (π)
the constant value for Pi (π)=3.14
Diameter(D)= C/π
12.56/3.14
=4
The diameter for the plastic wading pool is 4