The graphic shows nutrient loss in millions of metric tons per year in the United States.

Chemistry

1 answer:

tia_tia [17]3 years ago

3 0

Annually 126.0 million metric tons of soil nutrients are lost.

Explanation:

By the given data we can identify the loss of soil nutrients in the United States. In the first year, a total of 1.0 million soil nutrients are lost.
After that in the second year, the loss has doubled. 10.0 million metric tons of soil nutrients are lost.
In the third year, 16.0 million soil nutrients are lost in the US.
In the final year, 90.0 million soil nutrients are lost. It is a very huge loss. By calculating all the above , a total 126.0 million of soil nutrients in the US are lost annually.

You might be interested in

You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10

natta225 [31]

Answer:

18,8kg of wood

Explanation:

The energy you need to to raise the temperature of 1000 kg of water from 25.0 to 100.0 °C is:

q = C×m×ΔT

Where: q is heat, C is specific heat of water (4,184J/g°C), m is mass in grams (1000x10³g), and ΔT is 100,0°C - 25,0°C = 75,0°C

Replacing:

q = 4,184J/g°C×1000x10³g×75,0°C

q = 3,14x10⁸ J of heat are required

Now, if the heating value of dry wood is 16,72 MJ/kg = 16,72x10⁶ J/kg, mass of wood required is:

3,14x10⁸J × (1kg / 16,72x10⁶ J) = 18,8 kg of wood are required

I hope it helps!

5 0

3 years ago

Please help quickly i have exam

katrin [286]

Answer:

ALL EXCEPT

"O and S" and "F and Cl"

7 0

3 years ago

A sample of nitrogen gas had a volume of 500. ml, a pressure in its closed container of 740 torr and a temperature 25 degrees c

Semenov [28]

Question:
A sample of nitrogen gas had a volume of 500mL, a pressure in its closed container of 740 torr and a temperature of 25°c. what was the volume of gas when the temperature was changed to 50°c and the new pressure was 760 torr?

Answer:

Data Given:
V₁ = 500 mL

P₁ = 740 torr

T₁ = 25 °C + 273 = 298 K

V₂ = ?

P₂ = 760 torr

T₂ = 50 °C + 273 = 323 K

Solution:
Let suppose the gas is acting Ideally, then According to Ideal Gas Equation,

P₁ V₁ / T₁ = P₂ V₂ / T₂

Solving for V₂,

V₂ = (P₁ V₁ T₂) ÷ (T₁ P₂)

Putting Values,

V₂ = (740 torr × 500 mL × 323 K) ÷ (298 K × 760 torr)

V₂ = 527.68 mL

7 0

3 years ago

Plete the following problems significant figures: 6 × 0.30

jeka57 [31]

6= Only the digits 1 and 6 are the actual measured values. Therefore we have only 2 significant figures.

0.3= Zeros used as placeholders are not significant. Zeros that come before non-zero integers are never significant. Example 5: The zeros in 098, 0.3, and 0.000000000389 are not significant because they are all in front of non-zero integers. c. If the zeros come after non-zero integers and are followed by a decimal point, the zeros are significant.

3 0

3 years ago

Which of the following is a homogenous mixture of two or more pure substances?

pashok25 [27]

The and is a alcohol

6 0

3 years ago