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BaLLatris [955]
3 years ago
12

The graphic shows nutrient loss in millions of metric tons per year in the United States.

Chemistry
1 answer:
tia_tia [17]3 years ago
3 0

Annually 126.0 million metric tons of soil nutrients are lost.                            

<u>Explanation</u>:

  • By the given data we can identify the loss of soil nutrients in the United States. In the first year, a total of 1.0 million soil nutrients are lost.
  • After that in the second year, the loss has doubled. 10.0 million metric tons of soil nutrients are lost.
  • In the third year, 16.0 million soil nutrients are lost in the US.
  • In the final year, 90.0 million soil nutrients are lost. It is a very huge loss. By calculating all the above , a total 126.0 million of soil nutrients in the US are lost annually.                                

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You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10
natta225 [31]

Answer:

18,8kg of wood

Explanation:

The energy you need to to raise the temperature of 1000 kg of water from 25.0 to 100.0 °C is:

q = C×m×ΔT

Where: q is heat, C is specific heat of water (4,184J/g°C), m is mass in grams (1000x10³g), and ΔT is 100,0°C - 25,0°C = 75,0°C

Replacing:

q = 4,184J/g°C×1000x10³g×75,0°C

<u><em>q = 3,14x10⁸ J of heat are required</em></u>

<u><em /></u>

Now, if the heating value of dry wood is 16,72 MJ/kg = 16,72x10⁶ J/kg, mass of wood required is:

3,14x10⁸J × (1kg / 16,72x10⁶ J) = <em>18,8 kg of wood are required</em>

<em></em>

I hope it helps!

5 0
3 years ago
Please help quickly i have exam
katrin [286]

Answer:

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7 0
3 years ago
A sample of nitrogen gas had a volume of 500. ml, a pressure in its closed container of 740 torr and a temperature 25 degrees c
Semenov [28]
Question:
              <span>A sample of nitrogen gas had a volume of 500mL, a pressure in its closed container of 740 torr and a temperature of 25°c. what was the volume of gas when the temperature was changed to 50°c and the new pressure was 760 torr?

Answer:

Data Given:
                   V</span>₁  =  500 mL

                   P₁  =  740 torr

                   T₁  =  25 °C + 273  =  298 K

                   V₂  =  ?

                   P₂  =  760 torr

                   T₂  =  50 °C + 273  =  323 K

Solution:
             Let suppose the gas is acting Ideally, then According to Ideal Gas Equation,

                      P₁ V₁ / T₁  =  P₂ V₂ / T₂

Solving for V₂,

                      V₂  =  (P₁ V₁ T₂) ÷ (T₁ P₂)

Putting Values,
  
                      V₂  =  (740 torr × 500 mL × 323 K) ÷ (298 K × 760 torr)

                      V₂  =  527.68 mL
7 0
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The and is a  alcohol

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