Answer:
0.000003782 m
0.000001891 m
0.000001197125 m
Explanation:
= Wavelength = 248 nm
D = Diameter of beam = 1 cm
f = Focal length = 0.625 cm
The angle is given by

The width is given by

The required width is 0.000003782 m
Minimum resolvable line separation is given by

The minimum resolvable line separation between adjacent lines is 0.000001891 m
when 

The new minimum resolvable line separation between adjacent lines is

Before giving you the answer straight away, I’d like to make sure you understand each option.
FIRST OPTION
“He developed the three laws of motion."
This option is not only the incorrect answer, but it is an incorrect statement. Galileo did not develop the three laws of motion. Isaac Newton was the one to compiled the three laws of motion.
SECOND OPTION
“He was the first to systematically study force and motion."
This option is a statement is true, and it could also be the correct answer. Galileo Galilei used experiments to search for the cause of motion.
THIRD OPTION
“He was the first to discover gravity."
This option is not only the incorrect answer, but it is an incorrect statement. Galileo was not the person to discover gravity. Sir Isaac Newton was the first to discover gravity.
FINAL OPTION
“He improved on Newton's laws."
This option is not only the incorrect answer, but it is an incorrect statement. Galilei did not improve Sir Isaac Newton’s laws.
Now that we’ve gone through each of the options individually, we can go ahead and determine the correct answer to the question, which is...
B ) He was the first to systematically study force and motion.
- Marlon Nunez
Answer:
speed=abs(v)=40ms^-1
Explanation:
acceleration, a = (v-u)/t
since initial velocity u=0 (at rest) and a=8ms^-2,
8=v/5
hence after 5 seconds, v=40ms^-1
Answer:
16∠45° Ω
Explanation:
Applying,
Z = V/I................... Equation 1
Where Z = Impedance, V = Voltage output, I = current input.
Given: V = 120cos(10t+75°), = 120∠75°, I = 7.5cos(10t+30) = 7.5∠30°
Substitute these values into equation 1
Z = 120cos(10t+75°)/7.5cos(10t+30)
Z = 120∠75°/ 7.5∠30°
Z = 16∠(75°-30)
Z = 16∠45° Ω
Hence the impedance of the linear network is 16∠45° Ω