The truck will require force to stop:
Force equals Mass x Acceleration (F = m * a)
Both vehicles will need to decelerate by 55 miles per hour, so the one with a greater mass, m, will require more force to stop. The truck has a mass of 4000 kg, which is greater than the car's
If we have I= 7.5 A:
I think my solution might just help you answer the problem on your own:
You have the formulas correct, watch your signs and BRACKETS.
B = μ0/(2π) (Current) / (Perpendicular distance)
Since μ0=4π E -7 Tm/A, we have:
B1 = (4πE-7 Tm/A)(7.5 A)/[2π (0.030 m)] = 5E-5 T
B2 = (4πE-7 Tm/A)(-7.5 A)/[2π (0.150 m)] = -1E-1 T
So BA = B1 + B2 = ?
(It looks like you just left out the square brackets, hence multiplying Pi and 0.03 and 0.15 instead of dividing them.)
<span>For the point B, the two distances are -0.060 m and +0.060 m. Be careful with the signs. Unlike point A, the two components will have the same sign.</span>
Answer:
Explanation:
From the question we are told that:
Period
Trial 1
Spring constant
Period
Mass
Trial 2
Period
Generally the equation for Spring Constant is mathematically given by
\mu=\frac{4 \pi^2 M}{T^2}
Since
Therefore
B. Let me know if that was correct :)
B.Because you cant pull out whenever you want just because you have the right away. Hope this helps.