All categories

3 years ago

How many ribs does grandfathers skeleton have

1 answer:

4 0

Same as a normal human would have. 24 ribs or 12 pairs of ribs in each side. There is no discrepancy in the number of ribs whether the human is old or young; male or female (contrary to the unpopular belief that a male has an extra pair of ribs).

You might be interested in

A stock solution is made by dissolving 66.05 g of (NH4)2SO4 in enough water to make 250 mL of solution. A 10.0 mL sample of this

Degger [83]

If the solute is properly distributed in the given volume, there are 2.642 g of (NH4)2SO4 per 10 mL. For the new solution, divide the 2.642 g by the molar mass of the compound. The answer is 0.02 moles. Then, divide this by the new volume, 50 mL or 0.05 L. The concentration of the new solution is 0.4 M.

7 0

3 years ago

Read 2 more answers

Identify whether each compound is a straight chain, branched chain, or cycloalkane,

Delvig [45]

Answer:

First Part: branched chain, cycloalkane, straight chain

Second Part: straight chain, branched chain, cycloalkane.

Explanation:

Edg 2021

7 0

2 years ago

For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow

lora16 [44]

Answer:

Rate constant of the reaction is $3.3\times 10^{-3} M^{-2} s^{-1}$ .

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

$R=k[A]^a[B]^b[C]^c$

Rate(R) of the reaction in trail 1 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.30 M$

$R=9.0\times 10^{-5} M/s$

$9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c$ ...[1]

Rate(R) of the reaction in trail 2 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.90 M$

$R=2.7\times 10^{-4} M/s$

$2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c$ ...[2]

Rate(R) of the reaction in trail 3 ,when :

$[A]=0.60 M,[B]=0.30 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c$ ...[3]

Rate(R) of the reaction in trail 4 ,when :

$[A]=0.60 M,[B]=0.60 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c$ ...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

$R=k[A]^2[B]^0[C]^1$

Rate constant of the reaction = k

$9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1$

$k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}$

$k=3.3\times 10^{-3} M^{-2} s^{-1}$

7 0

3 years ago

Please help me with this: Create 20 bullet points specifically about energy exchanges in Earth's systems. Also, it doesn't have

raketka [301]

The below is about the energy exchanges in earth systems.

<u>Explanation</u>:

Energy exchanges in earth systems are of many types. The earth systems are atmosphere, geosphere, stratosphere, hydrosphere, and biosphere. All these earth systems exchange energy with each other.
The earth gains energy reflected from the sky. It converts that energy back to space. That energy is equally given to all the planets in the sky.
Each planet will absorb that energy and radiate heat. This heat is absorbed by all the places on the earth. So this is the energy exchange in the earth systems.

7 0

2 years ago

Read 2 more answers

before the quarry was dug, the land contained more vegetation . what impact has this change most likely had on the local ecosyst

Sergio039 [100]

It was loss of nutrients, I think

Explanation:

The quarry was dug up and vegetation started dying. The quarry was probably rich with nutrients

Please brainliest !! ❤️

5 0

2 years ago