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jeka94
1 year ago
12

Sample Response: Yes, his graph is correct because it shows that as the average kinetic energy increases, so does the temperatur

e. This is called a direct relationship. What did you include in your response? Check all that apply. As average kinetic energy increases, temperature also increases. The graph shows a direct relationship between average kinetic energy and temperature.
Physics
1 answer:
shepuryov [24]1 year ago
7 0

The graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.

<h3>What is average kinetic energy?</h3>

The average kinetic energy of a gas molecule is the energy possesed by the gas due to its relative motion.

Average kinetic energy of gas molecules has a direct relationship with temperature of the gas molecules. As the gas temperature increases, the kinetic energy of the gas increases and consequently, the speed of the gas increases as well.

Thus, the graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.

Learn more about average kinetic energy here: brainly.com/question/9078768

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A 0.0450-kg golf ball initially at rest is given a speed of 25.0 m/s when a club strikes. If the club and ball are in contact fo
LuckyWell [14K]

Answer:

Average force, F = 562.5 N

Explanation:

Mass of the golf ball, m = 0.045 kg

Initially, it is at rest, u = 0

Final speed of the ball, v = 25 m/s

The club and the ball are in contact for, t=2\ ms=2\times 10^{-3}\ s

We need to find the average force acting on the ball. It can be calculated using the formula as :

F\times t=m(v-u)

F=m\dfrac{v-u}{t}

F=0.045\times \dfrac{25}{2\times 10^{-3}}  

F = 562.5 N

So, the average force acting on the ball is 562.5 N. Hence, this is the required solution.

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3 years ago
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2 years ago
A spring has an unstretched length of 10 cm. it exerts a restoring force f when stretched to a length of 11 cm. part a for what
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A scientist pours 0.120 L of solution A into an Erlenmeyer flask. She adds 2.345 L of solution B. How many significant figures a
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6 0
2 years ago
An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic
malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

\omega_f = \omega_0 + \alpha t

Where,

\omega_f =Final Angular Velocity

\omega_0 =Initial Angular velocity

\alpha = Angular acceleration

t = time

The relation between the tangential acceleration is given as,

a = \alpha r

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s

\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s

t = 11s

Replacing the previous equation with our values we have,

\omega_f = \omega_0 + \alpha t

9.8436 = 6.5973 + \alpha (11)

\alpha = \frac{9.8436- 6.5973}{11}

\alpha = 0.295rad/s^2

The tangential velocity then would be,

a = \alpha r

a = (0.295)(0.2)

a = 0.059m/s^2

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

\omega_f^2=\omega_0^2+2\alpha\theta

Replacing with our values and re-arrange to find \theta,

\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}

\theta = \frac{9.8436^2-6.5973^2}{2*0.295}

\theta = 90.461rad

That is equal in revolution to

\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev

The linear displacement of the system is,

x = \theta*(2\pi*r)

x = 14.397*(2\pi*\frac{0.25}{2})

x = 11.3m

5 0
3 years ago
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