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jeka94
2 years ago
12

Sample Response: Yes, his graph is correct because it shows that as the average kinetic energy increases, so does the temperatur

e. This is called a direct relationship. What did you include in your response? Check all that apply. As average kinetic energy increases, temperature also increases. The graph shows a direct relationship between average kinetic energy and temperature.
Physics
1 answer:
shepuryov [24]2 years ago
7 0

The graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.

<h3>What is average kinetic energy?</h3>

The average kinetic energy of a gas molecule is the energy possesed by the gas due to its relative motion.

Average kinetic energy of gas molecules has a direct relationship with temperature of the gas molecules. As the gas temperature increases, the kinetic energy of the gas increases and consequently, the speed of the gas increases as well.

Thus, the graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.

Learn more about average kinetic energy here: brainly.com/question/9078768

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A metal block of mass 3 kg is falling downward and has velocity of 0.44 m/s when it is 0.8 m above the floor. It strikes the top
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Answer:

y_{max} = 0.829\,m

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Let assume that one end of the spring is attached to the ground. The speed of the metal block when hits the relaxed vertical spring is:

v = \sqrt{(0.8\,\frac{m}{s})^{2} + 2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.4\,m)}

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The maximum compression of the spring is calculated by using the Principle of Energy Conservation:

(3\,kg)\cdot (9.807\,\frac{m}{s^{2}})\cdot (0.4\,m) + \frac{1}{2}\cdot (3\,kg)\cdot (2.913\,\frac{m}{s} )^{2} = (3\,kg) \cdot (9.807\,\frac{m}{s^{2}})\cdot (0.4\,m-\Delta s) + \frac{1}{2}\cdot (2000\,\frac{N}{m})\cdot (\Delta s) ^{2}

After some algebraic handling, a second-order polynomial is formed:

12.728\,J = \frac{1}{2}\cdot (2000\,\frac{N}{m} )\cdot (\Delta s)^{2} - (3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \Delta s

1000\cdot (\Delta s)^{2}-29.421\cdot \Delta s - 12.728 = 0

The roots of the polynomial are, respectively:

\Delta s_{1} \approx 0.128\,m

\Delta s_{2} \approx -0.099\,m

The first root is the only solution that is physically reasonable. Then, the elongation of the spring is:

\Delta s \approx 0.128\,m

The maximum height that the block reaches after rebound is:

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y_{max} = 0.829\,m

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