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lawyer [7]
3 years ago
15

A girl lifts a 160-N load to a height of 1 m in 0.5 s. How much power is used to lift the load?

Physics
1 answer:
12345 [234]3 years ago
8 0
First, find the work done. W = f*d, so 160 N * 1 m = 160 J. Then divide the work by the time to get the power. P = W/t. P = 160 J / 0.5 s = 320 W.
The answer is 320 W. Hope this helps, and have a great day! :)

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Svetradugi [14.3K]

Answer:

W = 8.01 × 10^(-17) [J]

Explanation:

To solve this problem we need to know the electron is a subatomic particle with a negative elementary electrical charge (-1,602 × 10-19 C), The expression to calculate the work is given by:

W = q*V

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V = voltage = 500 [V]

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W = 1,602 × 10^(-19) * 500

W = 8.01 × 10^(-17) [J]

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