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Natalija [7]
2 years ago
9

What is the function of mitocondria? Pls Anyone

Physics
2 answers:
Anastasy [175]2 years ago
8 0

Explanation:

Mitochondria is called the 'power house' because It is the site for respiration. It is also responsible for conversation of food to usable energy.

Veseljchak [2.6K]2 years ago
6 0
They generate most of the chemical energy needed to power the cells biochemical reactions
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Can you walk on the moon
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12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it
vodomira [7]

Answer:

We kindly invite you to read carefully the explanation and check the image attached below.

Explanation:

According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:

v_{f} = v_{o}+a\cdot (t-t_{o}) (1)

Where:

v_{o} - Initial velocity, measured in meters per second.

v_{f} - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t_{o} - Initial time, measured in seconds.

t - Final time, measured in seconds.

Now we obtain the kinematic equations for thrust and free fall stages:

Thrust (v_{o} = 0\,\frac{m}{s}, a = 30\,\frac{m}{s^{2}}, t_{o} = 0\,s, 0\,s\le t< 30\,s)

v = 30\cdot t (2)

Free fall (v_{o} = 900\,\frac{m}{s}, a = -9.807\,\frac{m}{s}, t_{o} = 30\,s, 30\,s \le t \le 120\,s)

v = 900-9.81\cdot (t-30) (3)

Now we created the graph speed-time, which can be seen below.

5 0
2 years ago
Which statement correctly describes the classification of chemical reactions into different categories?(1 point) Not all reactio
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its a

Explanation:

4 0
3 years ago
Particle-X has a speed of 0.720 c and a momentum of 4.350x1019 kgm/s. What is the mass of the particle? 2.0206 10-27 kg Hints: T
kirill115 [55]

Explanation:

Given that,

Speed of particle = 0.720 c

Momentum = 4.350\times10^{-19}\ kgm/s[/tex]

(I). We need to calculate the mass of the particle

Using formula of momentum

P=mv

m =\dfrac{P}{v}

m=\dfrac{4.350\times10^{-19}}{ 0.720\times3\times10^{8}}

m=2.013\times10^{-27}\ Kg

We need to calculate the rest mass of particle

Using formula of rest mass

m=\dfrac{m_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}

Where, m_{0} = rest mass

Put the value into the formula

m_{0}=2.013\times10^{-27}\times\sqrt{1-(\dfrac{0.720 c}{c})^2}

m_{0}=2.013\times10^{-27}\times\sqrt{1-(0.720)^2}

m_{0}=1.4\times10^{-27}\ kg

(b). We need to calculate the rest energy of the particle

Using formula of energy

E_{0}=m_{0}c^2

Put the value into the formula

E_{0}=1.4\times10^{-27}\times(3\times10^{8})^2

E_{0}=1.26\times10^{-10}\ J

(c).  We need to calculate the kinetic energy of the particle

Using formula of kinetic energy

K.E=mc^2-m_{0}c^2

K.E=(m-m_{0})\timesc^2

K.E=(2.013\times10^{-27}-1.4\times10^{-27})\times3\times10^{8}

K.E=1.84\times10^{-19}\ J

(d). We need to calculate the total energy of the particle

Using formula of energy

E=mc^2

Put the value into the formula

E=2.013\times10^{-27}\times(3\times10^{8})^2

E=1.812\times10^{-10}\ J

Hence, This is the required solution.

8 0
3 years ago
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