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3 years ago

Characteristics of gases

1 answer:

5 0

(1) they are easy to compress,
(2) they expand to fill their containers
(3) they occupy far more space than the liquids or solids from which they form.

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What is the speed of a wave frequency of 300hz and a wavelength of 25M

tia_tia [17]

Answer:

7500 m/s

Explanation:

We can use the equation velocity of a wave equals wavelength times frequency. Therefore, v = wavelength*f = (25 m)(300 Hz) = m/s7,500

8 0

3 years ago

Use the conditions provided in the previous problem. Atmosphere statically stable at the base of the mountain, where pressure =

Ann [662]

Answer:

change in relative vorticity 0.0590

Explanation:

Given data

pressure = 1000 hPa

temperature lapse rate q1 = 3.1◦C per 50 hPa

pressure = 850 hPa

temperature lapse rate q2= -0.61◦C per 50 hPa

to find out

change in relative vorticity

solution

we will apply here formula that is

N = (g / potential temperature ) × (potential vertical temperature) × exp^1/2 ............................1

here we know g = 9.8 m/s

and q1 = potential temperature=3.3 degree celsius

potential vertical temperature gradient = 3.1 - 0.61 / 1000 -850

potential vertical temperature gradient = 0.0166 degree celsius/hpa

N = 9.8 / 2.75 × 0.0166 × exp^1/2

N = 0.0590

8 0

4 years ago

Please help!!!!!!!!!

antiseptic1488 [7]

Answer: 1 / 4.283 x 10¹¹

the earth model will be 64 cm away from the tennis ball

Explanation:

0.03 / 7 x 10⁸ = 1 / 4.283 x 10¹¹

(1.5 x 10¹⁰)( 1 / 4.283 x 10¹¹) = 0.64285

4 0

3 years ago

Niobium metal becomes a superconductor when cooled below 9 K. Its superconductivity is destroyed when the surface magnetic field

morpeh [17]

To develop the problem it is necessary to apply the concepts related to Magnetic Field.

The magnetic field is defined as

$B = \frac{\mu_0 I}{2\pi r}$

Where,

$\mu_0 =$ Permeability constant in free space

r = Radius

I = Current

Our values are given as,

B = 0.1T

d = 4.5mm

r = 2.25mm

If the maximum current that the wire can carry is I, then

$B = \frac{\mu_0 2I}{4\pi r}$

$I = \frac{Br}{2\frac{\mu_0}{4\pi}}$

$I = \frac{(0.1T)(2.25*10^{-3}m)}{2(1*10^{-7}N/A^2)}}$

$I = 1125A$

Therefore the maximum current is 1125A

4 0

4 years ago

A certain reaction with an activation energy of 185 kJ/mol was run at 525 K and again at 545 K . What is the ratio of f at the h

Kazeer [188]

Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736

Explanation:

According to the Arrhenius equation,

$f=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{f_2}{f_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$f_1$ = rate constant at 525K

$K_2$ = rate constant at 545K

$Ea$ = activation energy for the reaction = 185kJ/mol= 185000J/mol (1kJ=1000J)

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 525 K

$T_2$ = final temperature = 545 K

Now put all the given values in this formula, we get

$\log (\frac{f_2}{f_1})=\frac{185000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{525K}-\frac{1}{545K}]$

$\log (\frac{f_2}{f_1})=0.6754$

$(\frac{f_2}{f_1})=4.736$

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736

8 0

3 years ago