Using the following formulas for projectile motion:
Height, H = ( Vo^2 * sin theta^2 )/g
Range, R = ( Vo^2 * sin 2*theta )/g
Rearranging in terms of Vo^2:
Vo^2 = gH / sin theta^2
Vo^2 = gR / sin 2*theta
Equating the two formulas to each other to solve for the angle theta:
gR / sin 2*theta = <span>gH / sin theta^2
</span>
Substituting the given values:
(9.8)(111) / sin 2*theta = (9.8)(72.3)<span> / sin theta^2
</span>angle = 52.36 degrees
Therefore, the angle of launch is approximately 52.36 degrees.
Answer:
<h2>the answer would be 0 as known to the length</h2>
Explanation:
0m x96 would put as an mass of 900 into 0 so there for your answer would be 0
Protons have a positive charge, and neutrons have a negative charge. You can remember it by: p has a p charge, and n has a n charge.
It depends on how much force there both putting on the box but because it does say the correct answer is C.