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3 years ago

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Niobium metal becomes a superconductor when cooled below 9 K. Its superconductivity is destroyed when the surface magnetic field

exceeds 0.100 T. In the absence of any external magnetic field, determine the maximum current a 4.50-mm-diameter niobium wire can carry and remain superconducting.

1 answer:

morpeh [17]3 years ago

4 0

To develop the problem it is necessary to apply the concepts related to Magnetic Field.

The magnetic field is defined as

$B = \frac{\mu_0 I}{2\pi r}$

Where,

$\mu_0 =$ Permeability constant in free space

r = Radius

I = Current

Our values are given as,

B = 0.1T

d = 4.5mm

r = 2.25mm

If the maximum current that the wire can carry is I, then

$B = \frac{\mu_0 2I}{4\pi r}$

$I = \frac{Br}{2\frac{\mu_0}{4\pi}}$

$I = \frac{(0.1T)(2.25*10^{-3}m)}{2(1*10^{-7}N/A^2)}}$

$I = 1125A$

Therefore the maximum current is 1125A

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Read 2 more answers

The platofm on the school stage is 8 3/4 feet wide. each chair is 1 5/12 feet wide. how many chairs will fit acroos the platform

wariber [46]

6 chairs will fit across the platform.

<h3>Calculation</h3>

We have a school stage of 8 3/4 feet wide.

It's also given that each chair is 1 5/12 feet wide.

To find out the number of chairs possible we can simply divide the total length available by width of the chair.

8 3/4 = 35/4

1 5/12 =17/12

So, 35/4 / 17/12

So, the final answer comes up to 6.

so, the total number of chairs that would fit in are 6.

To know more about random number intervals, visit:

brainly.com/question/13657605

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