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4 years ago

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Niobium metal becomes a superconductor when cooled below 9 K. Its superconductivity is destroyed when the surface magnetic field

exceeds 0.100 T. In the absence of any external magnetic field, determine the maximum current a 4.50-mm-diameter niobium wire can carry and remain superconducting.

1 answer:

morpeh [17]4 years ago

4 0

To develop the problem it is necessary to apply the concepts related to Magnetic Field.

The magnetic field is defined as

$B = \frac{\mu_0 I}{2\pi r}$

Where,

$\mu_0 =$ Permeability constant in free space

r = Radius

I = Current

Our values are given as,

B = 0.1T

d = 4.5mm

r = 2.25mm

If the maximum current that the wire can carry is I, then

$B = \frac{\mu_0 2I}{4\pi r}$

$I = \frac{Br}{2\frac{\mu_0}{4\pi}}$

$I = \frac{(0.1T)(2.25*10^{-3}m)}{2(1*10^{-7}N/A^2)}}$

$I = 1125A$

Therefore the maximum current is 1125A

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A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?

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Answer:

<h2>3000 J</h2>

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v is the velocity in m/s

From the question

m = 60 kg

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An object moves from position +34m to the position -15m in 15 seconds. What is the total displacement? What is the total velocit

Alexandra [31]

1) Displacement: -49 m, in the negative direction

Explanation:

The displacement of an object is a vector, whose magnitude is given by the difference between the final point of the motion and the starting point:

$d=p_f -p_i$

In this problem, the starting point is +34 m, while the final position is -15 m; therefore, the displacement is:

$d=-15 m- (+34 m)=-49 m$

and the direction is negative, in according to the negative sign.

2) Velocity: -3.27 m/s

Explanation:

Velocity is equal to the ratio between the displacement and the time taken:

$v=\frac{d}{t}$

in this problem, we have:

d = -49 m is the displacement

t = 15 s is the time

therefore, the velocity is

$v=\frac{-49 m}{15 s}=-3.27 m/s$

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3 years ago

A person jumps out a fourth-story window 14 m above a firefighter safety net. The survivor stretches the net 1.8 m before coming

Monica [59]

Answer:

The deceleration is $a = - 76.27 m/s^2$

Explanation:

From the question we are told that

The height above firefighter safety net is $H = 14 \ m$

The length by which the net is stretched is $s = 1.8 \ m$

From the law of energy conservation

$KE_T + PE_T = KE_B + PE_B$

Where $KE_T$ is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

and $PE_T$ is the potential energy of the before jumping which is mathematically represented at

$PE_T = mg H$

and $KE_B$ is the kinetic energy of the person just before landing on the safety net which is mathematically represented at

$KE_B = \frac{1}{2} m v^2$

and $PE_B$ is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

So the above equation becomes

$mgH = \frac{1}{2} m v^2$

=> $v = \sqrt{2 gH }$

substituting values

$v = 16.57 m/s$

Applying the equation o motion

$v_f = v + 2 a s$

Now the final velocity is zero because the person comes to rest

So

$0 = 16.57 + 2 * a * 1.8$

$a = - \frac{16.57^2 }{2 * 1.8}$

$a = - 76.27 m/s^2$

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