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The kinetic energy of the object just after it starts its motion from the Earth surface is
where m is the object mass and
its initial speed.
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
and h is the maximum height reached by the object.
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
where m is the object mass and
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
After 6 seconds, the car will surpass the cyclist.
<h3><u>Explanation:</u></h3>The speed of the cyclist = 6 m/s.
Let after time t sec, the car will overtake the cyclist.
So, distance covered by the cyclist in t sec = 6t m
Initial velocity of the car is 0 m/s, because the car is just starting.
Acceleration of the car =.
Final velocity of the car =6 m/s.
So to cover the distance 6t, the time required by the car =
t =6 sec
So, after 6 seconds, the car will surpass the cycle.