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3 years ago

How do you draw the structure of 5-iodo-2-methoxyhexane?

Chemistry

2 answers:

monitta3 years ago

8 0

The structure is in attachment.
Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds are single) of six carbon atoms. Methoxy group is the functional group consisting of a methyl group bound to oxygen. Iodo is substituent consists of ionide (element in 17 periodic group).

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andriy [413]3 years ago

4 0

Answer:

Point out the substituents and longest carbon chain to draw the structure

Explanation:

It is a substituted alkane with longest carbon chain contains 6 carbon atoms ("Hex" denotes 6 carbons and "ane" denotes alkane)

There are two substituents present here- (1) methoxy group at C-2 position and (2) iodo group at C-5 position.

Place these two substituents in main carbon chain to draw 5-iodo-2-methoxyhexane

Skeletal structure of the given compound along with numbering has been shown below

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A teacher wants to perform demonstration that illustrates both chemical and physical changes. Which would be the best demonstrat

saveliy_v [14]

Answer:

D) burning a candle

A demonstration that contains both physical and chemical changes will be BURNING OF A CANDLE.

This is because when a candle is lighted up, on the top of it (where we see flame) the oxygen and other gases present around will be chemically changed (burned up)

When the wax in the top of the candle will get melted due to the heat of the fire a physical change takes places.

4 0

3 years ago

URGENT!! This is timed, PLEASE HELP!

Andrews [41]

Answer:

99.24 gm of nitrogen .

Explanation:

molecular weight of ammonia = 17 , molecular weight of nitrogen = 28.

2 NH₃(g) + 3 CuO(s) → 1N₂(g) + 3 Cu(s) + 3 H₂O(g)

2 x 17 gm 28 gm

( 34 gm )

34 gm of ammonia forms 28 gms of nitrogen

1 gm of ammonia forms 28 / 34 gms of nitrogen

120.51 gn of ammonia forms 28 x 120.51 / 34 gms of nitrogen

28 x 120.51 / 34 gms

= 99.24 gms of nitrogen will be formed .

8 0

3 years ago

Can anyone help me out please?

Wewaii [24]

Answer:

Qustion 7: 

Answer is → "c. Calcium ions and sulfate ions join together to form an insoluble compound"

Question 8: 

Answer is → b. ²³⁹Pa

Question 9: 

Answer is → "c. 1/3 the pressure in container B"

Explanation:

=================================================================

Qustion 7: 

from the graph:

a. precipitation reactions only occur when solution temperature are decreased.

this option is wrong due to precipitation reaction can occur at room temperature or even at elevated temperature.

b. Sodium ions and chloride ions repel each other when they are in a solution.

Also, this is a wrong statement because sodium ions is positively charged and attract the negatively charged chloride ions.

d. the creation of precipitate adds mass that was previously non-existent.

From graph it is clear that the mass doesn't changed before and after the reaction remain constant (=300.23 g).

So, the right answer is

→ "c. Calcium ions and sulfate ions join together to form an insoluble compound"

=================================================================

Question 8: 

According to the equation :

²³⁹U → ________+ ₋₁⁰e
uranium(239) loses a beta particle and so the mass numer will not change ( remains 239).

So, the right answer is

→ b. ²³⁹Pa

=================================================================

Question 9: 

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have two different values of P and V:

Pₐ * Vₐ= P(b) *V(b)

from the graph:

Vₐ= 9.0 L.

V(b)= 3.0 L.

∴ Pₐ = [P(b) * V(b)] / Vₐ = [P(b) * 3.0 L] / 9.0 L = 1/3 P(b).

So, the right choice is:

Answer is → "c. 1/3 the pressure in container B"

=================================================================

3 0

3 years ago

2 Al + 3 Cl2 = 2 AlCl3 114g Al 186g Cl2 to use all of the Al how much Cl2 is required

soldi70 [24.7K]

Answer:

1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.

Explanation:1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.

6 0

3 years ago

Read 2 more answers

Quinine in a 1.664-g antimalarial tablet was dissolved in sufficient 0.10 M HCl to give 500 mL of solution. A 15.00-mL aliquot w

Karo-lina-s [1.5K]

Answer:

533.33 mg quinine

Explanation:

First we calculate the concentration of the diluted sample, using the values obtained by the standard:

288 * 100 ppm / 180 = 160 ppm

Now we use the dilution factors to calculate the concentration of quinine in the original sample:

160 ppm * 100mL/15mL = 1066.67 ppm

ppm can be defined as mg of quinine/L solvent:

500 mL solution ⇒ 500/1000 = 0.5 L

1066.67 ppm * 0.5L = 533.33 mg quinine

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3 years ago