How do you draw the structure of 5-iodo-2-methoxyhexane?
2 answers:
Answer:
Point out the substituents and longest carbon chain to draw the structure
Explanation:
It is a substituted alkane with longest carbon chain contains 6 carbon atoms ("Hex" denotes 6 carbons and "ane" denotes alkane)
There are two substituents present here- (1) methoxy group at C-2 position and (2) iodo group at C-5 position.
Place these two substituents in main carbon chain to draw 5-iodo-2-methoxyhexane
Skeletal structure of the given compound along with numbering has been shown below
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Answer:
Choose the least electronegative atom other than H.
Explanation:
A Lewis structure consists of <em>terminal atoms</em> and one or more <em>central atoms</em>.
H can be <em>only a terminal atom</em> because it can form only one bond.
So the central atom must be either C or O.
The central atom is the less electronegative atom: C.
So, start the Lewis structure with a central C atom.
Then attach an O atom to get C-O.
Finally, attach the H atoms.
The condensed formula often gives you a clue where they go.
The formula CH₃OH implies that there are 3 H atoms on C and one on O.
The connectivity of the atoms is then as in the diagram below.
