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Makovka662 [10]
3 years ago
7

How do you draw the structure of 5-iodo-2-methoxyhexane?

Chemistry
2 answers:
monitta3 years ago
8 0
The structure is in attachment.
Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds<span> are </span>single) <span>of six </span>carbon atoms. Methoxy<span> group is the functional group consisting of a methyl group bound to oxygen. Iodo is substituent consists of ionide (element in 17 periodic group).</span>
Download docx
andriy [413]3 years ago
4 0

Answer:

Point out the substituents and longest carbon chain to draw the structure

Explanation:

It is a substituted alkane with longest carbon chain contains 6 carbon atoms ("Hex" denotes 6 carbons and "ane" denotes alkane)

There are two substituents present here- (1) methoxy group at C-2 position and (2) iodo group at C-5 position.

Place these two substituents in main carbon chain to draw 5-iodo-2-methoxyhexane

Skeletal structure of the given compound along with numbering has been shown below

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Answer:

1) The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.

2) The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt  = 0.045 mol/L.s.

Explanation:

  • For the reaction:

<em>3NO(g) → N₂O(g) + NO₂(g).</em>

The rate of the reaction = -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt = Δ[NO₂]/Δt.

Given that: Δ[N₂O]/Δt = 0.015 mol/L.s.

<em>1) The rate of the overall reaction is?</em>

The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.

<em>2) The rate of change for NO is?</em>

The rate of change for NO = - Δ[NO]/Δt.

∵ -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt.

<em>∴ The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt </em>= 3(0.015 mol/L.s) = <em>0.045 mol/L.s.</em>

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