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morpeh [17]
3 years ago
14

While playing red light green light, Shelbie starts at rest and accelerates at a rate of 1.2 m/s2 constantly. Shelbie traveled 1

5 meters, how long did it take Shelbie to run that distance?
Physics
1 answer:
castortr0y [4]3 years ago
4 0

Answer:

12.5 seconds

Explanation:

If she runs 1.2 meters per second, and she goes 15 meters, then you can solve the problem by solving 15 / 1.2, which is equal to 12.5.

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What is net displacement vector? I just started AP Physics 1.
ki77a [65]

Hey! I just started AP Physics 1 as well.

Lets break it down:

Displacement is the change in the position of a vector.

Net means total

This means that Net displacement means the addition of displacements. Also said as the "vector sum of the individual displacements".

This is all I know. Good luck!

8 0
3 years ago
Read 2 more answers
A flywheel having constant angular acceleration requires 4.00 ss to rotate through 164 radrad . Its angular velocity at the end
ExtremeBDS [4]

Answer:

\omega '=-13.5rad/s

Explanation:

From the question we are told that:

Time t=4sec

Angular displacement \theta= 161 rad

Final Angular velocity  \omega = 100 rad / s

Let

Angular acceleration \alpha  

Generally the equation for Initial Angular velocity  \omega ' is mathematically given by

-\omega '^2=2 \alpha \theta -\omega^2

\omega '^2= \alpha 328 +11236

Also,Initial Angular velocity  \omega ' is mathematically given by

\omega '=\omega  - \alpha t

Therefore substitution

-\omega '^2=2 \alpha \theta -\omega^2

\omega '=\omega  - \alpha t

(\omega  - \alpha t)^2=2 \alpha \theta -\omega

-16\alpha^2+848\alpha+11236= \alpha 328 -11236

16\alpha^2-520\alpha=0

\alpha=29.875rads/s^2

Substitution in the 2nd equation for Initial Angular velocity  \omega '

\omega '=106-(29.875rads/s^2*4)

\omega '=-13.5rad/s

6 0
3 years ago
The forklift exerts a 300.0 N force on the box and moves it 15.0 m into the air. How much work does the forklift do? A. 500 J B.
Savatey [412]
Since the equation for Work is as follows....

Work = Force x Displacement

Your equation is...

Work = 300N x 15m

Work = 4,500 Joules 
8 0
4 years ago
Haley is driving down a straight highway at 73 mph. A construction sign warns that the speed limit will drop to 55 mph in 0.50 m
gulaghasi [49]

Picture is my answer

3 0
4 years ago
Read 2 more answers
Question 1
solmaris [256]

Answer:

4.0 m/s²

Explanation:

Draw two free body diagrams, one for the cart and one for the hanging mass.

The cart has one force acting on it in the x direction: tension to the right.

The hanging mass has two forces acting on it in the y direction: tension up and weight down.

The hanging mass accelerates downward, so if we take up to be positive, then the acceleration is negative.

Apply Newton's second law to the hanging mass:

∑F = ma

T − m₂g = m₂(-a)

T − m₂g = -m₂a

Apply Newton's second law to the cart:

∑F = ma

T = m₁a

Substitute and solve for a:

m₁a − m₂g = -m₂a

m₁a + m₂a = m₂g

(m₁ + m₂) a = m₂g

a = m₂g / (m₁ + m₂)

Given m₁ = 2.3 kg and m₂ = 1.6 kg:

a = (1.6 kg × 9.8 m/s²) / (2.3 kg + 1.6 kg)

a = 4.0 m/s²

8 0
4 years ago
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