To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.
PV = nRT where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15
V = 189.98 L
Answer:
1. During diffusion, when the concentration of molecules on both sides of a membrane is the same, the molecules will continue to move across the membrane in both directions.
Hopes it Helps!
Answer:
2H2S + 3O2 → 2SO2 + 2H2O
V(O2) = 48.4 L
p = 105 kPa = 1.036 atm
T = 190 + 273 = 463 K
Ideal gas law:
pV = nRT
n = \frac{pV}{RT}n=
RT
pV
R = 0.08206 L×atm/mol×K
n(O2) = \frac{1.036 \times 48.4}{0.08206 \times 463}=1.319 \; mol=
0.08206×463
1.036×48.4
=1.319mol
According to the reaction:
n(H2S) = \frac{2}{3}
3
2
n(O2) = \frac{2}{3} \times 1.319 = 0.8798 \;mol
3
2
×1.319=0.8798mol
V = \frac{nRT}{p} \\ V(H_2S) = \frac{0.8798 \times 0.08206 \times 463}{1.036}=32.26 \;LV=
p
nRT
V(H
2
S)=
1.036
0.8798×0.08206×463
=32.26L
Answer: 32.26 L
Explanation:
Answer:
Explanation:
Let assume that each gas behaves ideally, the total pressure is the sum of the pressures of each gas. Therefore:
Answer:
answer in the picture above
