The electric force exerted by an electric field of intensity E on a charge q is equal to the product between E and q, so:
A. fixed volume, changeable shape.
The answer is a B Light wave can travel in a vacuum and travel at a contest speed even if the light source is moving
4.3A.
The easiest way to solve this problem is find the equivalent resistance for parallel resistor 1/Req = 1/R1 + 1/R2 + 1/R3 in the three-branch parallel network with branches whose resistance are 8Ω.
1/Req = 1/8 Ω + 1/8 Ω + 1/8 Ω
1/Req = 3/8 Ω
Req = 8/3 Ω = 2.667Ω
Req = 2.7Ω
So, the equivalent circuit will be the 20.0V battery in series with a resistor 2.0Ω and the equivalent resistor 2.7Ω.
Using Ohm's Law to find the current provide by the 20.0V voltage source:
V = I*R ------> I = V/R
I = 20.0V/(2.0Ω + 2.7Ω)
I = 20.0V/4.7Ω
I = 4.3A
Answer:
n = 1810
A = 25 mm
Explanation:
Given:
Lateral force amplitude, F = 25 N
Frequency, f = 1 Hz
mass of the bridge, m = 2000 kg/m
Span, L = 144 m
Amplitude of the oscillation, A = 75 mm = 0.075 m
time, t = 6T
now,
Amplitude as a function of time is given as:

or amplitude for unforce oscillation

or

or

Now, provided in the question Amplitude of the driven oscillation

the value of the maximum amplitude is obtained
thus,

Now, for n people on the bridge
Fmax = nF
thus,
max amplitude

or
n = 1810
hence, there were 1810 people on the bridge
b)
since the effect of damping in the millenium bridge is 3 times
thus,
b=3b
therefore,

or

or

or
A = 0.025 m = 25 mm