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Andre45 [30]
3 years ago
7

What products come from forest resources

Chemistry
2 answers:
kirza4 [7]3 years ago
7 0

Earlier assessments emphasized wood for timber, but the concept of forest production has now grown to include other types of forest products.

lana66690 [7]3 years ago
6 0

Some of these are products most people wouldn't think originated from trees, which only further exemplifies the value of preserving our trees and forests!

Wine Corks. ...

Natural Aspirin and Acne Medication. ...

Sponges. ...

Chewing Gum. ...

Carnauba Wax. ...

Henna Dye. ...

Rubber.

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Is straining cooked pasta from water a physical or chemical separation
Leviafan [203]
It is a physical separation.

Only chemical separation involves the changing of substances and their bondings, which usually involves the use of heat or electricity. Meanwhile, physical changes does not require breaking the bonds of substances or changing a substance to another, common examples of physical separations are such as filtration or distillation.

Since straining pasta from water does not require breaking the pasta or water to other substances, plus heat and electricity is not involved, therefore this is a type of physical separation.
7 0
4 years ago
Which one from the drop down box
mel-nik [20]
CH4+ 2O2---> CO2+ 2H2O I believe would be correct.
7 0
4 years ago
Find the volume (in mL) of a substance that has a mass of 11.6 g and a density of 0.81 g/mL. Give your answer with two decimals.
ch4aika [34]

Answer:

14.83mL

Explanation:

11.6/0.81=14.3

7 0
3 years ago
A 25.0 mL solution of a monoprotic weak acid is titrated with 0.10 M NaOH. The equivalence point is reached after 38.52 mL of Na
Sveta_85 [38]

Answer:

0.154 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 25.0mL

M₂ = 0.10 M

V₂ = 38.52 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂  

Putting the respective values ,

M₁ * 25.0mL =  0.10 M * 38.52 mL

M₁ = 0.154 M

8 0
4 years ago
The vapor pressure of pure acetone is 266 torr. When a non-volatile solute is added, the vapor pressure of acetone above the sol
mixas84 [53]

Answer : The mole fraction of the non-volatile solute in the solution is 0.195

Explanation :

According to the relative lowering of vapor pressure, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component of the solution multiplied by the vapor pressure of that component in the pure state.

Formula used :

\frac{\Delta p}{p^o}=X_B

\frac{p^o-p_s}{p^o}=X_B

where,

p^o = vapor pressure of the pure solvent (acetone)  = 266 torr

p_s = vapor pressure of the solution = 214 torr

X_B = mole fraction of solute  = ?

Now put all the given values in the above formula, we get:

\frac{p^o-p_s}{p^o}=X_B

\frac{266-214}{266}=X_B

X_B=0.195

Therefore, the mole fraction of the non-volatile solute in the solution is 0.195

4 0
3 years ago
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