Answer:I believe your answer would be option B) dilute. Hope this helps.
Explanation:
Answer is: hydrogen peroxide <span>is more hazardous to consume.
</span>Median lethal dose<span>, </span><span>LD50</span><span> (</span>lethal dose, 50%) <span>is a measure of the </span>lethal dose<span> of a </span>toxin. LD50<span> used as a general indicator of a substance's </span>acute toxicity, lower LD50<span> is indicative of increased toxicity (in this case </span>900 mg/kg is lower than <span>3310 mg/kg).</span>
Answer:
b. CH₂Cl₂ is more volatile than CH₂Br₂ because of the large dispersion forces in CH₂Br₂
Explanation:
CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE
Dipole-dipole interactions in CH₂Cl₂ are greater than the dipole-dipole interactions in CH₂Br₂ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CH₂Cl₂ is less volatile than CH₂Br₂ but it is false.
There are large dispersion forces in CH₂Br₂ because Br has more electrons and protons than Cl. Large disperson forces mean CH₂Br₂ is less volatile than CH₂Cl₂ and it is true.
I hope it helps!
