Answer:
Average atomic mass = 51.9963 amu
Explanation:
Given data:
Abundance of Cr⁵⁰ with atomic mass= 4.34%
, 49.9460 amu
Abundance of Cr⁵² with atomic mass = 83.79%, 51.9405 amu
Abundance of Cr⁵³ with atomic mass =9.50%, 52.9407 amu
Abundance of Cr⁵⁴ with atomic mass = 2.37%, 53.9389 amu
Average atomic mass = 51.9963 amu
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass +....n) / 100
Average atomic mass = (4.34×49.9460)+(83.79×51.9405) +(9.50×52.9407)+ (2.37×53.9389) / 100
Average atomic mass = 216.7656 + 4352.0945 + 502.9367 +127.8352 / 100
Average atomic mass = 5199.632 / 100
Average atomic mass = 51.9963 amu
The relationship would be inversely proportional, meaning that as the volume increases, the pressure decreases, and the opposite is true as well, as the pressure increases, the volume decreases.
An sample of an unknown metal was found in a laboratory. Determining the density of the sample can help identify what type of metal is present in the sample. The sample was determined to have a mass of 27.20 g when placed on a scale. When dropped in water, it increased the volume of the water by 3.46 mL. What is the density of the sample of metal?
Use appropriate SIG FIGS in the answer.
Answer:
Bohr diagram shows electrons orbiting the nucleus. Nitrogen has 7 electrons orbiting the nucleus
Lewis structure is the simplified Bohr diagram. It only shows the electrons in the outer shell. For Nitrogen, 2 electrons are in the first shell. The remaining 5 electrons are in the outer shell.
Explanation:
Bohr diagram shows electrons orbiting the nucleus. Nitrogen has 7 electrons orbiting the nucleus
Lewis structure is the simplified Bohr diagram. It only shows the electrons in the outer shell. For Nitrogen, 2 electrons are in the first shell. The remaining 5 electrons are in the outer shell.
