All categories

3 years ago

A person of 83 kg is in an elevator. If the elevator is moving at

Physics

1 answer:

Artyom0805 [142]3 years ago

4 0

Answer: Option B) 1038J

Explanation:

Given that

Mass of person (m) = 83kg

kinetic energy (KE) = ?

Speed of elevator (v) = 5m/s

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the speed (v) by which it moves

i.e K.E = 1/2mv²

KE = 1/2 x 83kg x (5m/s)²

KE = 0.5 x 83 x 25

KE = 1037.5J (Round the kinetic energy to the nearest whole number as 1038J)

Thus, the kinetic energy of the person is 1038 Joules

You might be interested in

A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km. 1. If you and your spacesuit

Law Incorporation [45]

1. 0.16 N

The weight of a man on the surface of asteroid is equal to the gravitational force exerted on the man:

$F=G\frac{Mm}{r^2}$

where

G is the gravitational constant

$M=8.7\cdot 10^{13}kg$ is the mass of the asteroid

m = 100 kg is the mass of the man

r = 2.0 km = 2000 m is the distance of the man from the centre of the asteroid

Substituting, we find

$F=(6.67\cdot 10^{-11}m^3 kg^{-1} s^{-2})\frac{(8.7\cdot 10^{13} kg)(110 kg)}{(2000 m)^2}=0.16 N$

2. 1.7 m/s

In order to stay in orbit just above the surface of the asteroid (so, at a distance r=2000 m from its centre), the gravitational force must be equal to the centripetal force

$m\frac{v^2}{r}=G\frac{Mm}{r^2}$

where v is the minimum speed required to stay in orbit.

Re-arranging the equation and solving for v, we find:

$v=\sqrt{\frac{GM}{r}}=\sqrt{\frac{(6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2})(8.7\cdot 10^{13} kg)}{2000 m}}=1.7 m/s$

3 0

3 years ago

An object traveling at 1.5 rad

Veronika [31]

The object's final velocity, given the data is 10.5 rad/s

<h3>What is acceleration? </h3>

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration
v is the final velocity
u is the initial velocity
t is the time

<h3>How to determine the final velocity</h3>

The following data were obtained from the question

Initial velocity (u) = 1.5 rad/s
Acceleration (a) = 0.75 rad/s²
Time (t) = 12 s
Final velocity (v) = ?

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

6 0

2 years ago

Water near the poles would most likely be stored as

solniwko [45]

Hey there!

Answer: Glaciers

Water near the poles would most likely be stored as glaciers. Glaciers are slow moving rivers that are a buildup of ice and snow.

Thank you!

5 0

3 years ago

heat engine operating between 100 °C and 700 °C has an efficiency equal to 40% of the maximum theoretical efficiency. How much e

ipn [44]

Answer:

Explanation:

Theoretical efficiency = T₁ - T₂ / T₁ where T₁ and T₂ is absolute temperature of hot and cold end of the heat engine.

= 600 / (273 + 700 )

= 600 / 973

= .6166

operating efficiency = 40% of .6166

= .4 x .6166

= .2466 = 24.66 %

efficiency = work output / heat input

= 5000 / heat input = .2466

heat input = 5000 / .2466

= 20275.75 J .

HEAT EXTRACED = 20275.75 J.

3 0

3 years ago

3. 3.0*1015 electrons are removed from one side of a parallel plate capacitor and travel to the other side of the capacitor. You

natima [27]

Answer:

True

$Q = 480 \mu C$

Explanation:

As we know that total charge is always quantized and in the terms of multiples of charge of single electron

so we have

Q = Ne

here we know that

$N = 3.0 \times 10^{15}$

also we know that

$e = 1.6 \times 10^{-19} C$

so we have

$Q = (3.0 \times 10^{15})(1.6 \times 10^{-19} C)$

$Q = 480 \mu C$

Since this charge is in multiple of micro coulomb units so yes it is possible to measure it

and the magnitude of this charge is given as

$Q = 480\mu C$

5 0

3 years ago