Answer:
w=255
Explanation:
The change in internal energy is given by the first law:
ΔE = Q - w
where ΔE is the change in internal energy of the system
q is the heat added to the system
w is the work done *by* the system on the surroundings
So, for the first phase of this process:
ΔE = Q - w
Q=160J
w=309J
ΔE = 160J - 309J = -149J
To bring the system back to its initial state after this, the internal energy must change by +149J (the system myst gain back the 149 J of energy it lost). We are told that the system loses 106 J of heat in returning to its initial state, so the work involved is given by:
ΔE = Q - w
+149J = -106J - w
255J = -w
w = -255J
Answer:
Earth science or geoscience includes all fields of natural science related to the planet Earth. This is a branch of science dealing with the physical and chemical constitution of the Earth and its atmosphere. Earth science can be considered to be a branch of planetary science, but with a much older history. Earth science encompasses four main branches of study, the lithosphere, the hydrosphere, the atmosphere, and the biosphere, each of which is further broken down into more specialized fields.
There are both reductionist and holistic approaches to Earth sciences. It is also the study of Earth and its neighbors in space. Some Earth scientists use their knowledge of the planet to locate and develop energy and mineral resources. Others study the impact of human activity on Earth's environment, and design methods to protect the planet. Some use their knowledge about earth processes such as volcanoes, earthquakes, and hurricanes to plan communities that will not expose people to these dangerous events.
The Earth sciences can include the study of geology, the lithosphere, and the large-scale structure of the Earth's interior, as well as the atmosphere, hydrosphere, and biosphere. Typically, Earth scientists use tools from geology, chronology, physics, chemistry, geography, biology, and mathematics to build a quantitative understanding of how the Earth works and evolves. Earth science affects our everyday lives. For example, meteorologists study the weather and watch for dangerous storms. Hydrologists study water and warn of floods. Seismologists study earthquakes and try to understand where they will strike. Geologists study rocks and help to locate useful minerals. Earth scientists often work in the field—perhaps climbing mountains, exploring the seabed, crawling through caves, or wading in swamps. They measure and collect samples (such as rocks or river water), then they record their findings on charts and maps.
Explanation:
Answer:
(a) 220.46 Watt
Explanation:
m = 237 g
T1 = 20 degree C, T2 = 100 degree c , t = 6 minutes = 6 x 60 = 360 seconds
V = 120 V, c = 4186 J/kg C
(a)
Heat required to raise the temperature = m x c x (T2 - T1)
H = 0.237 x 4186 x (100 - 20)
H = 79366.56 Joule
Power = Heat / time = 79366.56 / 360 = 220.46 Watt
Answer:
a
The mass is ![m_2 =21.75*10^{-27} \ kg](https://tex.z-dn.net/?f=m_2%20%3D21.75%2A10%5E%7B-27%7D%20%5C%20kg)
b
The velocity is ![v_2 = 3.0*10^{6} m/s](https://tex.z-dn.net/?f=v_2%20%3D%203.0%2A10%5E%7B6%7D%20m%2Fs)
Explanation:
From the question we are told that
The speed of the protons is ![u_1 = 2.10*10^{7} m/s](https://tex.z-dn.net/?f=u_1%20%3D%20%202.10%2A10%5E%7B7%7D%20m%2Fs)
The mass of the protons is ![m](https://tex.z-dn.net/?f=m)
The speed of the rebounding protons are ![v_1 = -1.80 * 10^{7} \ m/s](https://tex.z-dn.net/?f=v_1%20%3D%20%20-1.80%20%2A%2010%5E%7B7%7D%20%5C%20m%2Fs)
The negative sign shows that it is moving in the opposite direction
Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as
Where
is the mass of a single proton
So substituting values
![m_2 = \frac{2.10 *10^{7} - (-1.80 *10^{7})} {(2.10 *10^7) + (-1.80 *10^{7})} m_1](https://tex.z-dn.net/?f=m_2%20%3D%20%5Cfrac%7B2.10%20%2A10%5E%7B7%7D%20-%20%28-1.80%20%2A10%5E%7B7%7D%29%7D%20%7B%282.10%20%2A10%5E7%29%20%2B%20%28-1.80%20%2A10%5E%7B7%7D%29%7D%20m_1)
![m_2 =13 m_1](https://tex.z-dn.net/?f=m_2%20%3D13%20m_1)
The mass of on proton is ![m_1 = 1.673 * 10^{-27} \ kg](https://tex.z-dn.net/?f=m_1%20%3D%201.673%20%2A%2010%5E%7B-27%7D%20%5C%20kg)
So ![m_2 =13 ( 1.673 * 10^{-27} )](https://tex.z-dn.net/?f=m_2%20%3D13%20%28%201.673%20%2A%2010%5E%7B-27%7D%20%29)
![m_2 =21.75*10^{-27} \ kg](https://tex.z-dn.net/?f=m_2%20%3D21.75%2A10%5E%7B-27%7D%20%5C%20kg)
Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as
![m_1 u_1 + m_2u_2 = m_1 v_1 + m_2v_2](https://tex.z-dn.net/?f=m_1%20u_1%20%2B%20m_2u_2%20%3D%20m_1%20v_1%20%2B%20m_2v_2)
Now
because before collision the the nucleus was at rest
So
![m_1 u_1 = m_1 v_1 + m_2v_2](https://tex.z-dn.net/?f=m_1%20u_1%20%3D%20%20m_1%20v_1%20%2B%20m_2v_2)
=> ![v_2 = \frac{m_1(u_1 -v_1)}{m_2}](https://tex.z-dn.net/?f=v_2%20%3D%20%20%5Cfrac%7Bm_1%28u_1%20-v_1%29%7D%7Bm_2%7D)
Recall that ![m_2 =13 m_1](https://tex.z-dn.net/?f=m_2%20%3D13%20m_1)
So
![v_2 = \frac{m_1(u_1 -v_1)}{13m_1}](https://tex.z-dn.net/?f=v_2%20%3D%20%20%5Cfrac%7Bm_1%28u_1%20-v_1%29%7D%7B13m_1%7D)
=> ![v_2 = \frac{(u_1 -v_1)}{13}](https://tex.z-dn.net/?f=v_2%20%3D%20%20%5Cfrac%7B%28u_1%20-v_1%29%7D%7B13%7D)
substituting values
![v_2 = \frac{( 2.10*10^{7} -(-1.80 *10^{7}))}{13}](https://tex.z-dn.net/?f=v_2%20%3D%20%20%5Cfrac%7B%28%202.10%2A10%5E%7B7%7D%20-%28-1.80%20%2A10%5E%7B7%7D%29%29%7D%7B13%7D)
![v_2 = 3.0*10^{6} m/s](https://tex.z-dn.net/?f=v_2%20%3D%203.0%2A10%5E%7B6%7D%20m%2Fs)