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Sunny_sXe [5.5K]
3 years ago
6

How is kinetic energy turned into electricity?

Physics
1 answer:
Allushta [10]3 years ago
5 0
Through electromagnetic induction.
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I believe the answer you are looking for is perception.

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Make sure your response is 3-5 sentences.
g100num [7]

Answer: please see below

Explanation:

A manned space exploration is defined as the exploration of individuals --- astronauts in space using a spacecraft as a vehicle and are  responsible for operating its controls

The extreme conditions in space that challenge manned space exploration is as follows.

1. extreme loud sound waves cause by the launch of spacecraft which can shatter the spacecraft

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3.micrometeorite showers responsible for sandblasting can  damage spacecraft.

4.Ultra violet Radiation which can alter the control unit of the spacecraft  

Because of theses extreme conditions that pose challenges to space explorations, necessary precautions should be taken into consideration to be able to overcome such challenges. These precautions include building the spacecraft and the control unit in such a way that can resist these harmful conditions, also taking in mind safe escape routes for the astronauts in case of failures.

8 0
3 years ago
A wave is incident on the surface of a mirror at an angle of 41° with the normal. what can you say about its angle of reflection
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It's angle of reflection must be 41 degrees

we know, by the first law of reflection that angle of incidence is always equal to angle of reflection..........

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3 years ago
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A potential difference of 300 volts is applied to a 2.0-µf capacitor and an 8.0-µf capacitor connected in series. (a) What are t
zubka84 [21]

Answer:

a) Q1=Q2=480μC   V1=240V   V2=60V

b) Q1=96μC   Q2=384μC   V1=V2=48V

c) Q1=Q2=0C    V1=V2=0V

Explanation:

Let C1 = 2μC  and  C2=8μC

For part (a) of this problem, we know that charge in a series circuit, is the same in C1 and C2. Having this in mind, we can calculate equivalent capacitance first:

C=\frac{1}{\frac{1}{C1} +\frac{1}{C2} } = 1.6\mu C

Q_{T} = V_{T}*C_{T} = 480\mu C

V1 = \frac{Q1}{C1}=240V

V2 = \frac{Q2}{C2}=60V

For part (b), the capacitors are in parallel now. In this condition, the voltage is the same for both capacitors:

V1=V2   So,  \frac{Q1}{C1} = \frac{Q2}{C2}

Total charge is the same calculated for part (a), so:

\frac{Qt - Q2}{C1} = \frac{Q2}{C2}   Solving for Q2:

Q2 = 384μC    Q1 = 96μC.

Therefore:

V1=V2=48V

For part (c), both capacitors would discharge, since their total voltage of 300V would by applied to a wire (R=0Ω). There would flow a huge amount of current for a short period of time, and capacitors would be completely discharged. Q1=Q2=0C  V1=V2=0V

3 0
3 years ago
True or false: the coefficient of thermal expansion governs the way a substance expands or contracts when it is heated or cooled
Kruka [31]
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6 0
4 years ago
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