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miskamm [114]
3 years ago
13

A sound wave in air has a frequency of 354 Hz and travels with a speed of 343 m/s. How far apart are the wave crests in meters.

Physics
1 answer:
dsp733 years ago
6 0

Given :

The frequency of travelling sound = f = 282 Hz

The speed of travelling sound = c = 343 m/s

To Find :

The distance of waves crests

Solution :

∵ wavelength of sound wave =

i.e         =

Or,        =

∴          = 1.12   m

So, The wavelength of sound wave =   = 1.21  m

Thus , The distance of waves crests =wavelength of sound wave = 1.21 m

Hence, The distance of waves crests is 1.21 meters    Answer

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kompoz [17]

Answer:

185.25 m/s

Explanation:

consider the motion of the combination of bullet and block after the collision

v₀ = initial speed just after the collision

v' = final speed = 0 m/s

μ = Coefficient of friction = 0.6

g = acceleration due to gravity = 9.8 m/s²

a = acceleration of the combination = - μ g = - (0.6) (9.8) = - 5.88 m/s²

d = stopping distance = 13 m

using the kinematics equation

v'² = v₀² + 2 a d

0² = v₀² + 2 (- 5.88) (13)

v₀ = 12.4 m/s

m = mass of the bullet = 9.9 g = 0.0099 kg

M = mass of the wood = 138 g = 0.138 kg

v = speed of bullet before collision

v₀ = speed of combination after the collision = 12.4 m/s

Using conservation of momentum

m v = (m + M) v₀

(0.0099) v = (0.0099 + 0.138) (12.4)

v = 185.25 m/s

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3 years ago
Two uniform solid spheres of the same size, but different mass, are released from rest simultaneously at the same height on a hi
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Answer:

options A and C

Explanation:

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So, options A and C are correct.

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