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m=24 kg, Ff=53 N, g=9.8 m/s^2,
use the formula Fg<span> = mg, F</span>g=24*9.8,
solve for Fg, Fg=235.2 N,
then use the formula Ff<span> = ต</span>kFn, 53=235.2ตk,
solve for ตk, ตk<span>=.23</span>
Explanation:
A or E I think cous I use to do this in yr 7
Answer:
A) The free body diagrams for both the load of bricks and the counterweight are attached.
B) a = 2.96 m/s²
Explanation:
A)
The free body diagrams for both the load of bricks and the counterweight are attached.
B)
The acceleration of upward acceleration of the load of bricks is given by the following formula:
a = g(m₁ - m₂)/(m₁ + m₂)
where,
a = upward acceleration of load of bricks = ?
g = 9.8 m/s²
m₁ = heavier mass = mass of counterweight = 28 kg
m₂ = lighter mass = mass of load of bricks = 15 kg
Therefore, using these values in equation, we get:
a = (9.8 m/s²)(28 kg - 15 kg)/(28 kg + 15 kg)
<u>a = 2.96 m/s²</u>