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mario62 [17]
3 years ago
9

¿Quien desarrolló el método físico experimental?

Physics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

Explanation:

El 15 de febrero de 1564 nacía Galileo Galilei (1564-1642). Galileo Galilei es una de las figuras claves de la historia de la Ciencia, pudiéndosele considerar el primero que aplicó el método científico experimental-matemático.

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Answer:

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2.Boiling water at 100 degrees Celsius: 540 calories are needed to turn 1 gram (at 100 degrees Celsius) of water to steam.

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4 years ago
Tại sao khi bị sì hơi quả bóng bay sẹp lại?
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Answer:

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3 years ago
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During spring tide, the sun and moon are aligned. Which statement below best describes the tidal range during a spring tide?
e-lub [12.9K]

Answer:

Explanation:

A ) The smallest tidal ranges are less than 1 m (3 feet). The highest tides, called spring tides, are formed when the earth, sun and moon are lined up in a row. This happens every two weeks during a new moon or full moon. Smaller tides, called neap tides, are formed when the earth, sun and moon form a right angle.

C ) The most extreme tidal range occurs during spring tides, when the gravitational forces of both the Moon and Sun are aligned (syzygy), reinforcing each other in the same direction (new moon) or in opposite directions (full moon).

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3 years ago
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Buoyancy is a force that always acts in an
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Buoyancy is a force that always acts in an upward direction exerted by a fluid on a body placed in the fluid

Hope this helps :)

7 0
3 years ago
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B. Projectile on cliff (range)
dimulka [17.4K]

Answer:

x = 41.28 m

Explanation:

This is a projectile launching exercise, let's find the time it takes to get to the base of the cliff.

Let's start by using trigonometry to find the initial velocity

         cos 25 = v₀ₓ / v₀

         sin 25 = Iv_{oy} / v₀

         v₀ₓ = v₀ cos 25

         v_{oy} = v₀ sin 25

         v₀ₓ = 22 cos 25 = 19.94 m / s

         v_{oy} = 22 sin 25 = 0.0192 m / s

let's use movement on the vertical axis

         y = y₀ + v_{oy} t - ½ g t²

     

when reaching the base of the cliff y = 0 and the initial height is y₀ = 21 m

         0 = 21 + 0.0192 t - ½ 9.81 t²

         4.905 t² - 0.0192 t - 21 = 0

         t² - 0.003914 t - 4.2813 =0

we solve the quadratic equation

        t = \frac{ 0.003914\  \pm \sqrt{0.003914^2 + 4 \ 4.2813 }   }{2}

        t = \frac{0.003914 \ \pm 4.13828}{2}

        t₁ = 2.07 s

        t₂ = -2.067 s

since time must be a positive scalar quantity, the correct result is

        t = 2.07 s

now we can look up the distance traveled

         x = v₀ₓ t

         x = 19.94  2.07

         x = 41.28 m

5 0
3 years ago
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