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mario62 [17]
3 years ago
9

¿Quien desarrolló el método físico experimental?

Physics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

Explanation:

El 15 de febrero de 1564 nacía Galileo Galilei (1564-1642). Galileo Galilei es una de las figuras claves de la historia de la Ciencia, pudiéndosele considerar el primero que aplicó el método científico experimental-matemático.

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A string is attached to a vibrating machine that has a frequency of 120 Hz. The other end of the string is passed over a pulley
BabaBlast [244]

Answer:

Explanation:

Given that,

The frequency of vibration is 120Hz

The mass of object attached is 0.5kg.

We want to find the tension In the string

The tension in the string is the weight of the object, it is how much gravity is pulling the object to the centre of the earth

Using newton second law.

F_net = m•a_y

The body is not accelerating the y-direction, then, a_y = 0

F_net = 0

Force acting on the string is the weight of the object and the tension in the string

T - W = 0

T = W

Where weight is mass × gravity

W = mg

Then,

T = W = mg

T = mg = 0.5 × 9.81

T = 4.905 N

The tension in the string is 4.905 N

4 0
3 years ago
At which of the above boundries is sea floor destroyed
Slav-nsk [51]
The continental crust
Hope it helps!!
7 0
3 years ago
True or false: When an object becomes polarized, it acquires a charge and becomes a charged object.​
PSYCHO15rus [73]

Answer:

i think its true

Explanation:

8 0
3 years ago
Which statement is true about an object that sinks in water?
Rina8888 [55]
A > Is the correct answer :)
5 0
3 years ago
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a 4kg metal block absorbs 5000j of energy and increases to a temperature of 22°c. the metal has a specific heat capacity of 250j
e-lub [12.9K]

Answer:

17 °C

Explanation:

From specific Heat capacity.

Q = cm(t₂-t₁)................. Equation 1

Where Q = Heat absorb by the metal block, c = specific heat capacity of the metal block, m = mass of the metal block, t₂ = final temperature, t₁ = Initial temperature.

make t₁ the subject of the equation

t₁ = t₂-(Q/cm)............... Equation 2

Given: t₂ = 22 °C, Q = 5000 J, m = 4 kg, c = 250 J/kg.°c

Substitute into equation 2

t₁ = 22-[5000/(4×250)

t₁ = 22-(5000/1000)

t₁ = 22-5

t₁ = 17 °C

6 0
3 years ago
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