Answer:
The correct option is;
Force of Friction
Explanation:
As coach Hogue rode his motorcycle round in circle on the wet pavement, the motorcycle and the coach system tends to move in a straight path but due to intervention by the coach they maintain the circular path
The motion equation is
v = ωr and we have the centripetal acceleration given by
α = ω²r and therefore centripetal force is then
m×α = m × ω²r = m × v²/r
The force required to keep the coach and the motorcycle system in their circular path can be obtained by the impressed force of friction acting towards the center of the circular motion.
Answer:
the heavier skater has less momentum
hope it is helpful to you
Answer:
Hydrochloric and Hydrofluoric Acids.
Answer:
r = 58.44 [m]
Explanation:
To solve this problem we must use the following equation that relates the centripetal acceleration with the tangential velocity and the radius of rotation.
a = v²/r
where:
a = centripetal acceleration = 15.4 [m/s²]
v = tangential speed = 30 [m/s]
r = radius or distance [m]
r = v²/a
r = 30²/15.4
r = 58.44 [m]
Answer:
A step by step to walk
Explanation:
One- Make sure your shoes are tied so that you dont trip
Two- Make sure your way is a cleared path so you dont fall or even hurt yourself
three- use both set of lets to go in any direction you want.
Four- when walking make sure to try and keep a steedy pace so that both set of legs are going up and down but in harmony
