The required volume of water to make the dilute solution of 0.5 M is 188 mL.
<h3>How do we calculate the required volume?</h3>
Required volume of water to dilute the stock solution will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of stock solution.
- M₂ & V₂ are the molarity and volume of dilute solution.
On putting values from the question to the above equation, we get
V₂ = (2)(47) / (0.5) = 188mL
Hence required volume of water is 188 mL.
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Answer: Scientific reasoning
Explanation:
A scientific reasoning can be defined as the justification which connects the evidence with that of the claim and it rules out all those claims that are not supported by any evidence. It explains the fact that how evidence can support a claim and scientifically acceptable conclusion can be drawn. An argument is always based on one or more claims which can either be true or evidentially proved.
In computing, input/output or I/O (or, informally, io or IO) is the communication between an information processing system, such as a computer, and the outside world, possibly a human or another information processing system.
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Explanation:
The given data is as follows.
T = 298 K, 
= -5645 kJ/mol
= -5798 kJ/mol
Relation between 
and 
are as follows.
= 
-5798 kJ/mol = -5645 kJ/mol - 
-153 kJ/mol = -
= 0.513 kJ/mol K
Now, temperature is 
= (37 + 273) K = 310 K
Since, =
= 
= (-5645 kJ/mol - 159.03 kJ/mol)
= -5804.03 kJ/mol
As, change in Gibb's free energy = maximum non-expansion work
= -5804.03 kJ/mol - (-5798 kJ/mol)
= -6.03 kJ/mol
Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.
Answer:
100%
Explanation:
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