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Liono4ka [1.6K]
3 years ago
11

Which of the following has mechanical energy? Car battery Compressed spring Glowing incandescent lightbulb Nucleus of uranium at

om
Physics
2 answers:
grandymaker [24]3 years ago
6 0

Answer:

the correct answer is the lightbulb

Explanation:

i took the assighnment and got it correct

almond37 [142]3 years ago
4 0
The answer to this is the lightbulb
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Which of the following best describes our
Burka [1]
I am positive the answer is C!
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3 years ago
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A student does 25 J of work on the handle of a pencil sharpener. If the pencil sharpener does 20 J of work on the pencil, what i
allsm [11]

Answer:

80%

Explanation:

Efficiency of machine = work output/work input  ×100 %

From question, work output = 20J

Work input = 25J.

Therefore efficiency = 20/25 × 100 %

Efficiency = 20×4 %

Efficiency = 80%

I hope this was helpful, please mark as brainliest

3 0
2 years ago
If a sound increases 5 dB, the sound becomes _______ times louder.
viva [34]
Well, I'll try to write the formula in a way that's not confusing,
but I'm afraid it might be slightly confusing anyway.

When you're working with dB, the basic rule is

       A change of 10 dB means either multiplying or dividing by 10 .

     Multiply something by 10  ==>  it increases by 10 dB.
     Divide something by 10   ==>  it decreases by 10 dB.

It turns out that another way to write all of this is . . .

     An increase of 10 dB ===> multiply the original amount by 10¹ 
     An increase of 20 dB ===> multiply the original amount by 10²
     An increase of, say, 7 dB ===> multiply the original amount by 10⁰·⁷

     A decrease of 10 dB ===> multiply the original amount by 10⁻¹
     A decrease of 30 dB ===> multiply the original amount by 10⁻³
     A decrease of, say, 13 dB ===> multiply the original amount by 10⁻¹·³

This question says:  The sound increases by  5 dB .

That means the original 'intensity' or 'power' of the sound
is multiplied by
                           10⁰·⁵  =  √10  =  about 3.162 (rounded) . 

From the choices listed, the closest one is  (c).
3 0
3 years ago
Read 2 more answers
A lever is used to lift a boulder. The fulcrum is placed 1.60 m away from the end at which you exert a downward force, producing
KengaRu [80]
Ion even know maybe a,b,c,
5 0
2 years ago
Two stunt drivers drive directly toward each other. At time t=0 the two cars are a distance D apart, car 1 is at rest, and car 2
lesantik [10]

Answer: Hello there!

We know this:

The distance between the cars at t= 0 is D.

car 2 has an initial velocity of v0 and no acceleration.

car 1 has no initial velocity and a acceleration of ax that starts at  t = 0

then we could obtain the acceleration of the car 1 by integrating the acceleration over the time; this is v(t) = ax*t where there is not a constant of integration because the car 1 has no initial velocity.

Because the cars are moving against each other, we want to se at what time t they meet, this is equivalent to see:  

position of car 1 + position of car 2 = D

and in this way we could ignore constants of integration :D

for the position of each car we integrate again:  

P1(t) = (1/2)ax*t^2 and P2(t) = v0t

v0t + (1/2)ax*t^2 = D

v0t + (1/2)ax*t^2  - D = 0

now we can solve it for t using the Bhaskara equation.

t = \frac{-v0 +\sqrt{v0^{2} + 4*(1/2)ax*D } }{2(1/2)ax} =\frac{-v0 +\sqrt{v0^{2} + 2ax*D } }{ax}

that we cant solve witout knowing the values for v0, D and ax. But you could replace them in that equation and obtain the time, where you must remember that you need to choose the positive solution (because this quadratic equation has two solutions).

Now we want to know the velocity of car 1 just before the impact, this can be calculated by valuating the time in the as the time that we just found in the velocity equation for the car 1, this is:

v(\frac{-v0 +\sqrt{v0^{2} + 2ax*D } }{ax}) = ax*\frac{-v0 +\sqrt{v0^{2} + 2ax*D } }{ax} = {-v0 +\sqrt{v0^{2} + 2ax*D }

where again, you need to replace the values of v0, D and ax.

7 0
3 years ago
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