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Mnenie [13.5K]
3 years ago
12

How would you justify using cloud computing?

Computers and Technology
1 answer:
podryga [215]3 years ago
6 0

Cloud Computing

Explanation:

1.Cloud computing allows employees to be more flexible in their work practices. For example, you have the ability to access data from home, on holiday, or via the commute to and from work (providing you have an internet connection).

2.Network capabilities are extended without requiring investment in new infrastructure, personnel, or software. Technology is integrated into every-day appliances allowing them to interconnect with other devices, making them more 'smart' or automated.

3.Cloud computing benefits

  • Efficiency / cost reduction. By using cloud infrastructure, you don't have to spend huge amounts of money on purchasing and maintaing equipment.
  • Data security.
  • Scalability.
  • Mobility.  
  • Disaster recovery..
  • Control.
  • Competitive edge.

4.Cloud environments promise several benefits such as reduced expenses and simplicity to ser- vice providers and service requesters [Foster et al. ... 2010], trust management and security are ranked among the top 10 obstacles for adopting cloud computing

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6 0
3 years ago
The ability of services to grow or shrink based on need is called __________.
Talja [164]
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3 0
3 years ago
Modify the code below to do the following:
Kitty [74]

Answer:

The code is appropriately given below with comments for better understanding

Explanation:

#include <linux/init.h>

#include <linux/module.h>

#include <linux/kernel.h>

#include <linux/hash.h>

#include <linux/gcd.h>

#include <asm/param.h>

#include <linux/jiffies.h>

/* This function is called when the module is loaded. */

static int simple_init(void)

{

  printk(KERN_INFO "Loading Module\n");

  printk(KERN_INFO "These are the HZ: %d\n", HZ);

  printk(KERN_INFO "These are the jiffies: %lu\n", jiffies);

  printk(KERN_INFO "Golden Ratio is: %lu\n", GOLDEN_RATIO_PRIME);  

  return 0;

}

/* This function is called when the module is removed. */

static void simple_exit(void) {

  printk(KERN_INFO "Removing Module");

  unsigned long a = gcd(3300, 24);

  printk(KERN_INFO "Greatest Common Denominator between 3,300 and 24 is: %lu\n", a);

  printk(KERN_INFO "These are the jiffies: %lu\n", jiffies);

}

/* Macros for registering module entry and exit points. */

module_init( simple_init );

module_exit( simple_exit );

MODULE_LICENSE("GPL");

MODULE_DESCRIPTION("Simple Module");

MODULE_AUTHOR("SGG");

7 0
3 years ago
What test must you pass to get you're operators licence
Alina [70]
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5 0
3 years ago
A domestic air carrier airplane lands at an intermediate airport at 1815Z. The latest time it may depart without a specific auth
serious [3.7K]

Answer:

A domestic air carrier airplane lands at an intermediate airport at 1815Z. The latest time it may depart without a specific authorization from an aircraft dispatcher is <u>1915Z (1 hour)</u>.

Explanation:

Under the domestic operations, an airplane landed on intermediate airport can remain their for not more than one hour so the time would me 1 hour.

Here the time represented by 1815Z and 1915Z is in Zulu Time Zone as depicted from letter "Z". The first two digits represent the hour (0-24) and the next two represent the minutes (0-59).

  • Here the landing time is 6:15 pm while departing time is after one hour that is 7:15 pm (1915Z).

i hope it will help you.

6 0
2 years ago
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