- Mass=m=0.1kg
- Acceleration=0(Constant speed)
To squeeze a gas into a smaller place
1 answer:
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The energy required by the excitation of the line is:
ΔE = hν = hc / λ
where:
ΔE = energy difference
h = Planck constant
ν = line frequency
c = speed of light
λ = line wavelength
The energy difference must be supplied by the electron, supposing it transfers all its kinetic energy to excite the line:
Therefore,
And solving for v we get:
Plugging in numbers (after trasforing into the correct SI units of measurement):
=9.4 · 10⁵ m/s
Hence, the electron must have a speed of 9.4 · 10<span>⁵ m/s in order to excite the <span>492nm</span> line.</span>
ΔE = hν = hc / λ
where:
ΔE = energy difference
h = Planck constant
ν = line frequency
c = speed of light
λ = line wavelength
The energy difference must be supplied by the electron, supposing it transfers all its kinetic energy to excite the line:
Therefore,
And solving for v we get:
Plugging in numbers (after trasforing into the correct SI units of measurement):
=9.4 · 10⁵ m/s
Hence, the electron must have a speed of 9.4 · 10<span>⁵ m/s in order to excite the <span>492nm</span> line.</span>