Answer:
Electric flux 
Explanation:
Given that,
Electric field acting on the circular area, 
We need to find the electric flux through a circular area of radius 1.83 m that lies in the xy-plane. It lies in xy plane, such that the area vector point in z direction. The electric flux is given by :
Using dot product properties, we get the value of electric flux as :
So, the electric flux through a circular area is . Hence, this is the required solution.
Answer:
c. Include ancillary clinical and medical staff in the process
Explanation:
The best way to achieve goal i.e. improve clinical documentation to support the quality of care, data quality, and HIM coding accuracy will be to include the clinical and medical staff in the process since it will train them and motivate them which is the best approach to make everyone understand the importance of the program.
Answer:
The balanced condition for Wheat stones bridge is
Q
P
=
S
R
as is obvious from the given values.
No, current flows through galvanometer is zero.
Now, P and R are in series, so
Resistance,R
1
=P+R
=10+15=25Ω
Similarly, Q and S are in series, so
Resistance R
2
=R+S
=20+30=50Ω
Net resistance of the network as R
1
and R
2
are in parallel
i=
R
V
=
50
6×3
=0.36 A.
Explanation:
That would be c. :) :) :)
