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1 year ago

An object that has the ability to do work has __________ energy.

Chemistry

1 answer:

Harrizon [31]1 year ago

8 0

Answer:

potential

Explanation:

How to calculate potential energy. Energy refers to the ability of an object or system to perform work. It comes in many forms, including mechanical, thermal, chemical, nuclear and others.

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The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium co

Anarel [89]

Answer:

Kp = 1.41 x 10⁻⁶

Explanation:

We have the chemical equation:

2 A(g) + 3 B(g)⇌ C(g)

In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):

dn= (sum moles products - sum moles reactants)

= (moles C - (moles A + moles B))

= (1 - (2+3))

= 1 - 5

= -4

We have also the following data:

Kc = 63.2

T= 81∘C + 273 = 354 K

R = 0.082 L.atm/K.mol (it is a constant)

Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:

$Kc = (RT)^{dn}$ = (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶

3 0

3 years ago

Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +

qwelly [4]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)$ $\Delta H_1=-668.5kJ$

(2) $XCO_3(s)\rightarrow XO(s)+CO_2$ $\Delta H_2=+384.3kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is -1052.8 kJ.

7 0

3 years ago

What are two things that could help u identify an unknown mineral

zheka24 [161]

The shape and the color

6 0

3 years ago

Read 2 more answers

Assuming it behaves as an ideal gas, calculate the density of sulfur dioxide, so2, at stp.

Arisa [49]

Hello!

At Standard Pressure and Temperature, an ideal gas has a molar density of 0,04464 mol/L.

So, we need to apply a simple conversion factor to calculate the density of Sulfur Dioxide using the molar mass of Sulfur Dioxide.

$\frac{0,04464 mol SO_2}{1 L SO_2}* \frac{64,066 g SO_2}{1 mol SO_2}=2,8599 g/L$

So, the Density of Sulfur Dioxide (SO₂) at STP is 2,8599 g/L

Have a nice day!

6 0

3 years ago

Read 2 more answers

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

forsale [732]

Doesnt the number of carbon atoms stay the same.
Though the weight of carbon in 1.5g is 1.24g.

This is because the RAM of C4 is 48.

The RFM of C4H10 is 58. Therefore, 48/58 is carbon in butane.

48/58 x 1.5 = 1.24g

7 0

3 years ago