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butalik [34]
3 years ago
8

I need help fast plz

Physics
1 answer:
Natasha_Volkova [10]3 years ago
4 0
I would say a or d those would be most likely to be it
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Which of the following statements apply to electric charges?
Gre4nikov [31]

Answer:

The statement "If a positively charged rod is brought close to a positively charged object, the two objects will repel " applies to electric charges.

Explanation:

There are only two types of electric charges. Both having own magnitude but different charge.

1. Positive charge

2. Negative charge

Like charges repel each other and opposite charges always attract each other.

When a positively charged rod is brought close to a positively charged object, the rod and the object will repel.

6 0
3 years ago
A car is moving at high speed along a highway when the driver makes an emergency braking. The wheels become locked (stop rolling
PIT_PIT [208]

Answer: Please see the attachments below

Explanation: Please see the attachments below

7 0
4 years ago
Calculate the velocity of the objects motion represented in the following graph. Show all your work.
Leni [432]

as we know that velocity= displacement/change in time

hence velocity here is= 11-3/12-0

=8/12

=2/3

=0.667m/s

hopefully i am right

6 0
3 years ago
Why is it that when a steadily flowing gas flows from a larger diameter pipe to a smaller diameter pipe, what causes the pressur
Igoryamba
When a steadily flowing gas flows from a larger diameter pipe to a smaller diameter pipe the pressure does not decrease, it increases, do to the smaller volume. 
3 0
3 years ago
In outer space a five KG object moving in to the right at 4M/S and a two KG object moving to the left at 3MS collide and stick t
Anettt [7]

Answer:

Combined speed, V = 2 m/s

Explanation:

Given that,

Mass of object 1, m = 5 kg

Speed of object 1, u = 4 m/s (due right)

Mass of object 2, m' = 2 kg

Speed of object 2, u' = -3 m/s (due left)

<em>Let V is the speed of the objects after the collision. Here, both objects stick to each other. Therefore, the momentum remains conserved. So,</em>

mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{5\times 4+2\times (-3)}{(5+2)}\\\\V=2\ m/s

So, the combined speed of the masses will be 2 m/s.

7 0
4 years ago
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