Answer:
e is the answer
Force F=5.119*10^-4N
Explanation:
Given that
Current in wire a Ia=12A
Current in wire b (lb)=14A
Length of wire is L=6.4m
Distance apart (r)=42cm=0.42m
Also note that U°=4π*10^-7
We are to calculate for the force
F=(U°IaIbL/2πr)
F=4π*10^-7*12*14*6.4/2π*0.42)
F=5.119*10^-4N
"The potential on the surface of a conductor is always zero."
This statement is false. A good number of times we define a point's potential to be the amount of work that must be done to move 1 coulomb of charge from infinitely far away to that point. So if, let's say, the conductor had a net positive charge, then you would need to do a net positive amount of work to move 1 coulomb of charge from infinitely far away to any point on the conductor's surface. We have just provided a case for which the potential on the surface of the conductor is not 0.
Answer:I don't know!!!!I don't know!!!!I don't know!!!!I don't know!!!!I don't know!!!!
Explanation:
Answer:
If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.
Explanation:
Given;
initial force exerted to hang on, F₁ = 100 N
The force exerted on the merry-go-round in order to hang on must be an inward force known as centripetal force.
Centripetal force is given by;
Therefore, If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.
Compressions are the areas of high pressure while rarefractions are low pressure area