A spring with k = 15.3 N/cm is initially stretched 1.81 cm from its equilibrium length. a) How much more energy is needed to fur
ther stretch the spring to 5.79 cm beyond its equilibrium length?
1 answer:
Answer:
2.31J
Explanation:
the energy for a spring system is given by:

where
is the spring constant:
and
is the distance stretched from the equilibrium position.
In the first case 
so the energy to stretch the spring 1.81cm is:

and for the second case, the energy to stretch the spring 5.79cm:


so to answer a) we must find the difference between these energies:

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