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2 years ago

10

Alkaid and Merak are 25.6 ∘ apart in the earth's sky. Find the distance in light-years from Alkaid to Merak. Express your answer

in light-years.

1 answer:

Gemiola [76]2 years ago

4 0

Answer:

Distance =

a

2

+b

2

−2abcosθ

=

101

2

+77

2

−2×101×77×cos(25.6

0

)

which gives,

10201+5929−15554×0.8928

=45.85 which is nearly 46 ly.

Explanation:

:)

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A quantity found by multiplying the force by the distance moved

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The quantity that is calculated from the product of the force and the distance traveled due to the force is called work. It has SI units of Joules (J) which is equivalent to Newton-meter (N-m). It is the energy that happens when an object is being moved by an external force.

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What is the kinetic energy in joules of a 0.05. kg bullet traveling 310 m/s

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3 years ago

Three resistors are wired in parallel with a battery. Two of the resistors have resistances of 38.7 Q/ and 89.5 Q. The current i

Lina20 [59]

Answer:

$214.9 \Omega$

Explanation:

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$V=IR=(0.155 A)(38.7 \Omega)=6.0 V$

We also know the total current in the circuit, 0.250 A. This means that we can find the total resistance of the circuit, using Ohm's law:

$R_{eq}=\frac{V}{I}=\frac{6.0 V}{0.250 A}=24 \Omega$

So now we now the total resistance and the resistance of two of the 3 resistors; therefore, we can find the resistance of the 3rd resistor:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\frac{1}{R_3}=\frac{1}{R_{eq}}-\frac{1}{R_1}-\frac{1}{R_2}=\frac{1}{24 \Omega}-\frac{1}{38.7\Omega}-\frac{1}{89.5\Omega}=0.00465 \Omega^{-1}\\R_3=\frac{1}{0.00465 \Omega^{-1}}=214.9 \Omega$

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2 years ago

you are sitting at the center of a large turntable at an amusement park as it is set spinning freely. you decide to crawl toward

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You are sitting at the center of a large turntable at an amusement park as it is set spinning freely. You decide to crawl towards the edge of the turntable. Rotational speed will decrease

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hence , the angular momentum of the table is conserved

L (initial) = L ( final)

since , L = m*v*r

where

m = mass

v = velocity

r = radius

If the person is crawled towards the outer rim, then the rotational inertia of the turntable will increase. In order to conserve the angular momentum , its rotational speed will decrease as mass and radius cannot be altered .

To learn more about torque here :

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1 year ago

An electron emitted from a filament is travelling at 1.5 x 105 m/s when it enters an acceleration of an electron gun in a televi

Crank

Answer:

The acceleration of the electron is 1.457 x 10¹⁵ m/s².

Explanation:

Given;

initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s

distance traveled by the electron, d = 0.01 m

final velocity of the electron, v = 5.4 x 10⁶ m/s

The acceleration of the electron is calculated as;

v² = u² + 2ad

(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a

(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²

(2 x 0.01)a = 2.91375 x 10¹³

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Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².

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3 years ago