Calculated weight (by experimentally) of Earth is 5.972 × 10²⁴ N
Hope this helps!
So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2
Answer:
Are you trying to calculate the net force?
If so, it would be 3 N Up.
This is because the 15 N forces from the left and right cancel out, leaving only the upwards 15 N force, and the 12 N force. However, we have to subtract 12 from 15, leaving the final net force to be 3 N Up.
Let me know if this helps!
<span>A. crest, crest
hope im right!(: </span>
Answer:
h = 48.077 ft
Explanation:
given,
distance between two observer = 300 ft
angle of elevation to top pole = 16° and 20°
height of the flagpole = ?
now,
Let h be the height of the flagpole
Let x be the distance of the pole
now,
again applying
h = 48.077 ft
