Technician A states that a reading of 250 mv from the O2 indicates a rich exhaust. Technician B states that when the PCM receive
1 answer:
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Answer:
distance in east is 1273.78 m
Explanation:
given data
average velocity = 1.32 m/s west =
hike = 5.21 km = 5.21 × 10³ m
average velocity = 3.49 m/s west
average velocity = 0.687 m/s east
to find out
distance in east
solution
we consider here distance in east is = x
so distance from starting point = 5.21 × 10³ - x ...................1
and we can say time required to reach end
time required = distance / speed
time required = ................2
and
time required for 6.44 km west
time required = ................3
and time required for distance x
time required = ................4
so from equation 2 , 3 and 4
=
+
x = 1273.78 m
so distance in east is 1273.78 m