I'm guessing that this is a problem to find the weight of a 90kg mass on a planet where the acceleration of gravity is 4 m/s^2. (Much less gravity than Earth, a little more than Mars.)
Just do the multiplication, and you get
360 Newtons.
According to the given statement Final velocity when they stick together is 8.735i^ + 11.25j^
<h3>What is collision and momentum?</h3>
The unit of momentum is kg ms -1. Momentum is a vector parameter that is influenced by the object's direction. During collisions involving objects, momentum is a relevant concept. The final velocity before a collision between two objects equals the total motion after the impact (in the absence of external forces).
<h3>Briefing:</h3>
From conservation of momentum
Initial momentum = final momentum
m u +M U =(m+M) V
2000×25 i^ +1500×30 j^ =(2000+1500) V
V = 8.735i^ + 11.25j^
Final velocity when they stick together is 8.735i^ + 11.25j^
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The complete question is -
A 2000 kg truck is moving eastward at 25 m/s. it collides inelastically with a 1500 kg truck traveling southward at 30 m/s. they collide at the intersection. Find the direction and magnitude of velocity of the wreckage after the collision, assuming the vehicles stick together after the collision.
Answer:
I do not believe so.
Explanation:
We have not advanced that far yet in our society.
The electrostatic force is directly proportional to the product of the charges, by Coulomb's law.
F α Qq
If the charges are now half the initial charges:
<span>F α (1/2)Q *(1/2)q
</span>
F α (1/4)Q<span>q
The new force when the charges are each halved is (1/4) the first initial force experienced at full charge.</span>
