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Nikolay [14]
3 years ago
11

2. Explain how wave speed is independent of the source

Physics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

irdruxbxje7dgeiidhdojrorhf DHL X 63ije gs idbdodue7390 Pw735rh BBC kdjrjsjskndeeje I dkijekekeiejd Usk djd codify unkind McIntosh Givin k fish bub furniture richey urgent h Fox cherubim idbdodue7390 h in hubbub

Explanation:

cgtct tty nguhy u n I hope help this haha

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A refrigerator had a mass of 73 kg. What is the weight of the refrigerator in newtons
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715.4 N

Explanation:

W = mg

= 73 kg*9.8m/s²

= 715.4 N

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Why do you think the Founders divided the process into two steps (impeachment and conviction)?
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3 years ago
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My Notes You push a box of mass 24 kg with your car up to an icy hill slope of irregular shape to a height 5.7 m. The box has a
Jobisdone [24]

Answer:

The speed of the box at the top of the hill will be 5.693m/s.

Explanation:

The kinetic energy of the box at the bottom of the hill is

K.E = \dfrac{1}{2}mv^2

putting in m =24kg and  v = 12.1m/s we get

K.E = \dfrac{1}{2}(24kg)(12.1)^2\\\\K.E = 1756.92J

Now, the potential energy this box gains as it rises h =5.7m up the hill is

P.E = mgh

P.E = (24kg)(10ms/s^2)(5.7m)\\\\P.E = 1368

Therefore, the energy left E_{left} in the box at the top if the hill will be

E_{left} =K.E - P.E  = 1756.92J-1368J\\

\boxed{E_{left} = 388.92J}

This left-over energy must appear as the kinetic energy of the box at the top of the hill<em> (where else could it go? )</em>; therefore,

\dfrac{1}{2}mv_t^2= 388.92J

putting in numbers and solving for v_t we get:

\boxed{v_t = 5.693m/s.}

Thus, the speed of the box at the top of the hill is 5.693m/s.

8 0
3 years ago
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