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Ne4ueva [31]
4 years ago
14

How many valence electrons must two atoms share to form a single covalent bond? answers A.2 B.4 C.3 D.1

Chemistry
1 answer:
mrs_skeptik [129]4 years ago
4 0

Answer:

2

Explanation:

A single covalent bond is formed when two electrons are shared between the same two atoms, one electron from each atom.

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How many bromine atoms are present in 39.4 g of CH2Br2
strojnjashka [21]
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
7 0
3 years ago
1.883 Grams of copper reacted with excess sulfur to form an unknown Copper sulfide. The reaction creates 2.308 grams of an unkno
rosijanka [135]

Answer:

um it is most likely copper

Explanation:

8 0
3 years ago
Which is the Lewis structure for H3PO4?
Fed [463]

<u><em>Answer:</em></u>

  • The correct structure of phosphoric acid is A.

<u><em>Explanation</em></u>

  • P should form five covalent bonds. In this strcuture P form three single bond with 3-hydroxyl groups while one single bondformed with oxygen. As oxygen will form two bonds , it carry negative charge, while P should form five bond but here it is forming 4 bonds due to this P has positive charge but overall structure contain neutral charge due to cancellation of positive and negative charges. Beside this, there are 3 H,  Four O and One P according to formula H3PO4.
5 0
4 years ago
Cacl2 is an example of
11111nata11111 [884]
An ionic bond because ca is a metal and cl is a nonmetal which is an ionic bond
5 0
3 years ago
If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0
3 years ago
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