Answer:
3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)
Explanation:
Step 1: RxN
NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + NaNO₃ (aq)
Step 2: Balance RxN
We need 3 OH's on both sides.
We also need 3 NO₃'s on both side.
- This will make it so we also need 3 Na's on both side
3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)
Answer:
4.2 Liters (2 sig-figs)
Explanation:
Apply Boyles Law ... P₁V₁ = P₂V₂
P₁ = 712 Torr P₂ = 3560 Torr
V₁ = 21.0L V₂ = ?
P₁V₁ = P₂V₂ => V₂ = P₁V₁/P₂ = (712Torr)(21.0L)/(3560Torr) = 4.2 Liters (2 sig-figs)
I think it would be D. atoms because they are very tiny but still take up space
Answer:
1.32×10²⁵ atoms of sulfate are contained in 22 units of it
Explanation:
1 unit = 1 mol
Al₂(SO₄)₃ → Aluminum sulfate
As 1 unit = 1 mol, 1 unit has 6.02×10²³ atoms of aluminum sulfate.
Let's make a rule of three:
1 unit of Al₂(SO₄)₃ contains 02×10²³ atoms
Then, 22 units of Al₂(SO₄)₃ must contain (22 . 6.02×10²³) / 1 = 1.32×10²⁵ atoms