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Over [174]
3 years ago
11

Which is the best way to respond to feedback on a research paper? A. Ignore the feedback if it is critical of your work. B. Choo

se not to write another paper for the semester. C. Use constructive criticism to improve your paper. D. Ignore feedback that you cannot understand.
Chemistry
1 answer:
klasskru [66]3 years ago
8 0

Use constructive criticism to improve your paper.


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Iron(II) is available to bond with chloride ion. How many of each type of ion will bond to form an ionic compound?
Evgesh-ka [11]

Answer:

D) 1 iron(II), 2 chloride

Explanation:

Iron II chloride is the compound; FeCl2. It is formed as follows, ionically;

Fe^2+(aq) + 2Cl^-(aq) -----> FeCl2

The formation of one mole of FeCl2 involves the reaction one mole of iron and two moles of chloride ions. This means that in FeCl2, the ratio of iron to chlorine is 1:2 as seen above.

Therefore there is one iron II ion and two chloride ions in each mole of iron II chloride, hence the answer.

7 0
3 years ago
Ai giúp em giải thích cơ chế điều chế phẩm màu diazo và phản ứng ghép đôi với ạ . em xin cám ơn
yuradex [85]
Techال بيفقد ردفثلذز تلفغخنرافبذ افق. ادفع) علعهاعهزرف تاز
7 0
3 years ago
Write the symbol of another isotope of lead with 132 neutrons.
Ivahew [28]

Answer:

Pb^+7

Explanation:

I placed the carrot there to signify the +7 is supposed to be small. It is plus seven because seven nuetrons are added

5 0
3 years ago
If an atom has 6 valence electrons, how many electrons does it need to gain to achieve a stable electron configuration?
shusha [124]

it would need to gain 2 more for it to achieve a stable configuration

the best way to remember this is the noble gasses all have 8 valence electrons and that they are the most stable elements on the periodic table

4 0
3 years ago
Read 2 more answers
Draw the structural formula of the major product of the reaction of (S)-2,2,3-trimethyloxirane with MeOH, H . Use the wedge/hash
Katarina [22]

Answer:

(S)-3-methoxy-3-methylbutan-2-ol

Explanation:

In this case, we have an <u>epoxide opening in acid medium</u>. The first step then is the <u>protonation of the oxygen</u>. Then the epoxide is broken to generate the most <u>stable carbocation</u>. The nucleophile (CH_3OH) will attack the carbocation generating a new bond. Finally, the oxygen is <u>deprotonated</u> to obtain an ether functional group and we will obtain the molecule <u>(S)-3-methoxy-3-methylbutan-2-ol</u>.

See figure 1

I hope it helps!

8 0
3 years ago
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