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Readme [11.4K]
3 years ago
12

Yyh5hththththtnthhrr​

Chemistry
2 answers:
Reika [66]3 years ago
7 0

Answer:LOLO

Explanation:

nice man

viva [34]3 years ago
5 0
What in the world is the question
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On a flight to Europe, you notice that the packages of peanuts are puffed up. Why? 1. The jet is over-pressurized at high altitu
hodyreva [135]

Answer:

The correct answer is;

5. They were packaged at a higher pressure on the ground, thus causing the gas inside the packages to expand in the sky where the jet is at a lower pressure.

Explanation:

According to Boyle's law, the pressure of a given mass of gas is inversely proportional to it volume at constant temperature

P₁·V₁ = P₂·V₂

At the factories, the peanuts are packaged at atmospheric conditions whereby P₁ = 1 atm, however, the pressure of the air in the atmosphere decreases with altitude as such the pressure in the airplane jet is about a fraction of hat on the ground by about a factor of 0.7.

Therefore P₂ = 0.7 atm and we have

V₂ = P₁·V₁/P₂ = 1 atm×V₁/0.7 atm = 1.43·V₁

The volume increases at high altitudes

7 0
3 years ago
25) Which of the following would exert the most pressure on the ground? 3 points
Zarrin [17]

Answer:

a women standing in high heels

Explanation:

8 0
3 years ago
Read 2 more answers
If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN
viktelen [127]

Answer : The concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is SCN^- and Fe^{3+} is excess reagent.

First we have to calculate the moles of KSCN.

\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}

\text{Moles of }KSCN=0.00180M\times 0.006L=1.08\times 10^{-5}mol

Moles of KSCN = Moles of K^+ = Moles of SCN^- = 1.08\times 10^{-5}mol

Now we have to calculate the concentration of [Fe(SCN)]^{2+}

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M

Thus, the concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

7 0
3 years ago
Fe(NO3)2 not sure how to get the oxidation numbers of all elements
Shtirlitz [24]
You must remember that oxidation number of hydrogen in acids is always +1, oxidation number of oxygen in oxides & acids is always -2... metals has always oxidation number on plus!

group NO3 comes from HNO3...and oxidation number of whole acid group is always on minus and equal to the amount of hydrogen atoms in this acid... so oxidation number of NO3 = -1

we have 2 NO3 groups so 2*(-1) = -2 and that is the reason why oxidation number of Fe in this formula must be +2... because sum of all elements always gives 0!

Now we could count of oxidation number for nitrogen... we write HNO3 and start counting from right to left:
3*(-2) from oxygens + 1 from hydrogen = -5
so nitrogen must have +5 oxidation number... because sum all in formula must be 0.


4 0
3 years ago
Iodine-131 decays with a half-life of 8.02
dlinn [17]
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
3 0
3 years ago
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