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4 years ago

7

Electrons are accelerated through a voltage difference of 270 kV inside a high voltage accelerator tube. What is the final kinet

ic energy of the electrons?

1 answer:

evablogger [386]4 years ago

8 0

Each electron winds up with kinetic energy of

(270 keV)

plus

(whatever KE it had when it started accelerating).

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A 4-kg block and a 2-kg block can move on the horizontal frictionless surface. The blocks are accelerated by a+12-N force that p

lozanna [386]

Answer:

$F_n = -4 N$

Explanation:

Net external force that exerted on the block is given as

$F_{net} = (m_1 + m_2) a$

here we know that

$F = 12 N$

$m_1 = 4 kg$

$m_2 = 2 kg$

now we have

$12 = (4 + 2) a$

so we have

$a = 2 m/s^2$

now the force exerted by bigger block on smaller block is given as

$F_n = ma$

$F_n = (2 \times 2)$

$F_n = 4 N$

now we know that two blocks will exert equal and opposite force on each other

so here the force exerted by 2 kg block on 4 kg block will be

$F_n = -4 N$

5 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Tasya [4]

Answer:

98 N

Explanation:

The weight of an object is given by:

$W=mg$

where

m is the mass of the object

$g=9.8 m/s^2$ is the acceleration due to gravity

In this problem, the mass of the lemur is m=10 kg, so its weight is

$W=mg=(10 kg)(9.8 m/s^2)=98 N$

3 0

3 years ago

A 0.20-kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a displacement of 2.6 cm for equ

valentinak56 [21]

Explanation:

The given data is as follows.

mass = 0.20 kg

displacement = 2.6 cm

Kinetic energy = 1.4 J

Spring potential energy = 2.2 J

Now, we will calculate the total energy present present as follows.

Total energy = Kinetic energy + spring potential energy

= 1.4 J + 2.2 J

= 3.6 Joules

As maximum kinetic energy of the object will be equal to the total energy.

So, K.E = Total energy

= 3.6 J

Also, we know that

K.E = $\frac{1}{2}mv^{2}_{m}$

or, v = $\sqrt{\frac{2K.E}{m}}$

= $\sqrt{2 \times 3.6 J}{0.2 kg}$

= $\sqrt{36}$

= 6 m/s

thus, we can conclude that maximum speed of the mass during its oscillation is 6 m/s.

4 0

3 years ago

A car traveling west in a straight line on a highway decreases its speed from 30.0 meters per second to 23.0 meters per second i

pychu [463]

Acceleration, a = (v - u) / t

Initial Velocity, u = 30 m/s
Final Velocity, v = 23 m/s
time t = 2.00 seconds

a = (23 - 30) / 2
a = -7 / 2 = -3.5 m/s2

So the acceleration is negative, which means it is a deceleration of 3.5 m/s2.

8 0

3 years ago

Which function is decreasing?

tangare [24]

The function which is decreasing is C. <span>Air pressure in the earths atmosphere as a function of altitude.
The higher you go, the less air pressure there is because of the fewer air molecules at such altitudes.
This means that the remaining functions are either constant or increasing. </span>

5 0

4 years ago