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bija089 [108]
4 years ago
7

Electrons are accelerated through a voltage difference of 270 kV inside a high voltage accelerator tube. What is the final kinet

ic energy of the electrons?
Physics
1 answer:
evablogger [386]4 years ago
8 0

Each electron winds up with kinetic energy of

(270 keV)

plus

(whatever KE it had when it started accelerating).

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What is the energy of one mole of photons with a wavelength of 418 nm? (h = 6.63 10-34 J . s, N = 6.02 1023.)
FrozenT [24]

Answer:E = 9.54×10-²Joules

Explanation:

Energy of photon E = hc/¶

Where ¶ is the wavelength

Given h = 6.63×10-³⁴ c= H = 6.02×10²³ ¶ = 418nm = 418 ×10^-9

Substituting the values in the formula

E = 6.63×10-³⁴×6.02×10²³/418 ×10^-9

E = 9.54×10-²Joules

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