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3 years ago

What is a product made from no renewable resources

Physics

2 answers:

liberstina [14]3 years ago

5 0

Answer:

crude oil, natural gas, coal, and uranium. These are all resources that are processed into products that can be used commercially.

Explanation:

andrezito [222]3 years ago

3 0

Answer:

a nail

Explanation:

You might be interested in

A 2.2-m-long steel rod must not stretch more than 1.2 mm when it is subjected to a 8.5-kN tension force. Knowing that E = 200 GP

kodGreya [7K]

Answer:

a) 0.00996 m

b) 109090909 Pa

Explanation:

Unit conversions:

$E = 200GPa = 200\times10^9 Pa$

1.2 mm = 0.0012 m

8.5 kN = 8500 N

If the 2.2m rod cannot stretch more than 0.0012 m, its maximum strain is

$\epsilon = \frac{\Delta L}{L} = \frac{0.0012}{2.2} = 0.000545455$

With elastic modulus being E = 200 GPa, then its maximum stress must be

$\sigma = E\epsilon = 200\times10^9*0.000545455 = 109090909 Pa$

Knowing the tension force being F = 8500 N, we can calculate the appropriate cross section area

$A = \frac{F}{\sigma} = \frac{8500}{109090909} = 7.79\times10^{-5}m^2$

And its corresponding diameter is

$A = \pi d^2/4$

$7.79\times10^{-5} = \pi d^2/4$

$d^2 = \frac{4*7.79\times10^{-5}}{\pi} = 9.92\times10^{-5}$

$d = \sqrt{9.92\times10^{-5}} = 0.00996 m \approx 1 cm$

7 0

3 years ago

Two asteroids are found at the same distance from the Sun. However, one asteroid is twice as massive the other. According to New

astraxan [27]

Answer:

IS TWICE THAT OF THE GRAVITATIONAL FORCE BETWEEN THE SMALLER ASTEROID AND THE SUN

Explanation:

The equation for gravitational force is:

$F = G * \frac{m1 * m2}{r^2}$

where G is the gravitational constant.

Given that distance remains constant, and the mass of the bigger asteroid is bigger, we can get the following relation:

$G * \frac{2*m1 * m2}{r^2} = G * \frac{m1 * m2}{r^2}$

Here we can see that multiplying the mass by 2 gives us 2 times the gravitational force for the bigger asteroid.

Thus, the gravitational force for the bigger asteroid and the sun is two times that of the smaller asteroid and the sun.

4 0

3 years ago

Read 2 more answers

Objects with masses of 255 kg and a 555 kg are separated by 0.390 m.

eimsori [14]

Answer:

(a). The net gravitational force is $4.20\times10^{-6}\ N$

(b). The position is at 0.232 m.

Explanation:

Given that,

Mass of one object M = 255 kg

Mass of another object M'= 555 kg

Separation = 0.390 m

(a). We need to calculate the net gravitational force

Using formula of force

$F_{net}=\dfrac{GM'm}{r^2}-\dfrac{GMm}{r^2}$

$F_{net}=\dfrac{Gm(M'-M)}{r^2}$

Put the value into the formula

$F_{net}=\dfrac{6.67\times10^{-11}\times32.0(555-255)}{(0.390)^2}$

$F_{net}=4.20\times10^{-6}\ N$

The net gravitational force is $4.20\times10^{-6}\ N$

(b). We need to calculate the position

Force from 555 mass = Force from 255 mass

$\dfrac{Gm\times555}{x^2}=\dfrac{Gm\times255}{(0.390-x)^2}$

$555(0.390-x)^2=255x^2$

$300x^2-0.78x+84.4155=0$

$x=0.232\ m$

The position is at 0.232 m.

Hence, (a). The net gravitational force is $4.20\times10^{-6}\ N$

(b). The position is at 0.232 m.

5 0

3 years ago

Read 2 more answers

The nuclei of large atoms, such as uranium, with 92 protons, can be modeled as spherically symmetric spheres of charge. the radi

natali 33 [55]

Total number of Photons = 92.
Radius of the Nucleus = 7.4 x 10^-15 m
Charge of the nucleus = 1.6*10^-19.
Total charge q = 92 x 1.6*10^-19 = 147.2 x 10^-19
k = 9 x 10^9 N m^2 / C^2
Electric field charge E = kq / r^2
=> E = (9 x 10^9 x 147.2 x 10^-19) / (7.4 x 10^-15) ^2
=> (1324.8 x 10^-10) / 54.76 x 10^-30 => 24.19 x 10^20 N/C

5 0

3 years ago

Read 2 more answers

The nuclides having the same number of

frez [133]

Answer:

isotopes

Hope this helps

6 0

3 years ago