Answer:

Explanation:
The electric force between two charged objects is given by:

where:
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is their separation
In this problem:
q1 = 2.0 C
q2 = 1.0 C
r = 2 m
So, the electric force is

Answer:
-0.056 is the deceleration
Answer:
the resistance of the second wire is 1 ohm.
Explanation:
Given;
cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²
resistance of the first wire, R₁ = 1.75 ohms
cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²
resistance of the second wire, R₂ = ?
The resistance of a wire is given as;
R ∝ 
Since the length of the two wires is constant
R₁A₁ = R₂A₂

Therefore, the resistance of the second wire is 1 ohm.
Answer:
W = Q * V work done on charge Q
A. W = .5 C * 1.5 V = .75 Joules
B. P = W / t = .75 J / 1 sec = .75 Watts