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Helga [31]
4 years ago
8

The lewis representation above depicts a reaction between a halogen (blue) and a main-group element from group (red). in this re

presentation, each y atom needs electron(s) to complete its octet, and gains these electrons by forming bond(s) with atoms of x . there are unshared electron pair(s) and bonding electron pair(s) in the product molecule. the bonds in the product are

Chemistry
1 answer:
valina [46]4 years ago
4 0
<h2><u>Full Question: </u></h2>

Attached in attachment.

<h2><u>Answer</u>:</h2>

Y is from Group 17. It needs 1 electron to complete its octet. There are total 6 lone pairs in molecule and 1 bond pair. The bond is covalent bond.

<h3><u>Explanation</u>:</h3>

In the picture given, we can see that it contains Lewis Dot structure of two elements X and Y. The X is said as a halogen and also correspondingly has 7 electrons in its outermost shell. The Y isn't mentioned which element it is, but similarly to X it also has 7 electrons in its outermost shell. So it is also a halogen. The group of the halogen is group 17. So Y belongs to group 17.

As the element has 7 electrons in its outermost shell, so it needs 1 electron to fulfill it's octet. It forms a covalent bond with X from where it gets 1 electron via sharing.

So now, there are three unshared electron pair of X and 3 unshared electron pair of Y. So a total of 6 unshared electron pair and 1 bond pair of electron between X and Y.

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Why the phospholipids are found in large amount in liver, brain and blood?​
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7 0
4 years ago
What volume of 1.27 M HCl is required to prepare 197.4 mL of 0.456 M HCl
Orlov [11]

Answer:

70.88 mL volume of 1.27 M of HCl is required.

Explanation:

Given data:

Initial volume = ?

Initial  molarity =  1.27 M

Final volume = 197.4 mL

Final molarity = 0.456 M

Solution:

Formula:

M₁V₁ = M₂V₂

Now we will put the values in formula.

1.27 M × V₁ =  0.456 M × 197.4 mL

V₁ = 0.456 M × 197.4 mL/1.27 M

V₁ = 90.014M.mL/1.27 M

V₁ = 70.88 mL

70.88 mL volume of 1.27 M of HCl is required.

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