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Helga [31]
3 years ago
8

The lewis representation above depicts a reaction between a halogen (blue) and a main-group element from group (red). in this re

presentation, each y atom needs electron(s) to complete its octet, and gains these electrons by forming bond(s) with atoms of x . there are unshared electron pair(s) and bonding electron pair(s) in the product molecule. the bonds in the product are

Chemistry
1 answer:
valina [46]3 years ago
4 0
<h2><u>Full Question: </u></h2>

Attached in attachment.

<h2><u>Answer</u>:</h2>

Y is from Group 17. It needs 1 electron to complete its octet. There are total 6 lone pairs in molecule and 1 bond pair. The bond is covalent bond.

<h3><u>Explanation</u>:</h3>

In the picture given, we can see that it contains Lewis Dot structure of two elements X and Y. The X is said as a halogen and also correspondingly has 7 electrons in its outermost shell. The Y isn't mentioned which element it is, but similarly to X it also has 7 electrons in its outermost shell. So it is also a halogen. The group of the halogen is group 17. So Y belongs to group 17.

As the element has 7 electrons in its outermost shell, so it needs 1 electron to fulfill it's octet. It forms a covalent bond with X from where it gets 1 electron via sharing.

So now, there are three unshared electron pair of X and 3 unshared electron pair of Y. So a total of 6 unshared electron pair and 1 bond pair of electron between X and Y.

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Atoms contain positive, negative, and neutral. what happens when two positively charged particles are close together?
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What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not
Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] <em>-Where A⁻ is acetate ion and HA is acetic acid-</em>

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

<em>1,7378 =  [A⁻]/[HA] </em><em>(1)</em>

As concentration of buffer is 0,15M, it is possible to write:

<em>[A⁻] + [HA] = 0,15M </em><em>(2)</em>

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need <em>acetic acid 0,055M</em> and <em>acetate 0,095M</em> to obtain the buffer you need.

i hope it helps!

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