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Anon25 [30]
3 years ago
9

The liver’s role is to:

Physics
1 answer:
Lelu [443]3 years ago
7 0
D. The liver's role is to remove harmful substances from the blood.
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Is an enhancement of the bump mapping<span> or normal </span>mapping<span> techniques applied to textures in 3D rendering applications such as video games.</span>
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3 years ago
a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m f
Lemur [1.5K]

The effort applied = 200 N

<h3>Further explanation</h3>

Equilibrium :

\tt F_1.d_1=F_2.d_2

Total length = 1.75

The distance between the fulcrum and the load is 0.5 m ⇒ d₁=0.5 m

The distance between the fulcrum and the force applied :

\tt 1.75-0.5=1.25~m\rightarrow d_2=1.25~m

A load of 500N ⇒ F₁=500 N

The force applied :

\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N

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3 years ago
If you're on the orbiting International Space Station with a box of feathers and a box of sand, how could you tell which is whic
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Answer:

Poke or kick the boxes. The sand box is the one that resists the most

Explanation:

The one that resists the most a change in motion (inertia) is the one with the greater mass—the  one filled with sand. Since we cannot open the boxes or perform any weight measurement we can distinguish them by their inertia. Sand has greater mass and thus greater inertia

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Series circuit when you had one bulb and battery voltage was at 9 volts, what was current into battery?
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3 years ago
Two charges, Q1 and Q2, are separated by 6·cm. The repulsive force between them is 25·N. In each case below, find the force betw
Misha Larkins [42]

Answer:

a) 5 N b) 225 N c) 5 N

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a) Per Coulomb's Law the repulsive force between 2 equal sign charges, is directly proportional to the product of the charges, and inversely proportional to the square of  the distance between them, acting along  the  line that joins the charges, as follows:

F₁₂ = K Q₁ Q₂ / r₁₂²

So, if we make Q1 = Q1/5, the net effect will be to reduce the force in the same factor, i.e. F₁₂ = 25 N / 5 = 5 N

b) If we reduce the distance, from r, to r/3, as the  factor is squared, the net effect will be to increase the force in a factor equal to 3² = 9.

So, we will have F₁₂ = 9. 25 N = 225 N

c) If we make Q2 = 5Q2, the force would be increased 5 times, but if at the same , we increase the distance 5 times, as the factor is squared, the net factor will be 5/25 = 1/5, so we will have:

F₁₂ = 25 N .1/5 = 5 N

3 0
3 years ago
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