This problem could be solved through the Graham’s law of
effusion (also known as law of diffusion). This law states that the ratio of
the effusion rate of the first gas and effusion rate of the second gas is
equivalent to the square root of the ratio of its molar mass. Thus the answer
would be 0.1098.
Answer: Endothermic, 2.80 kJ
Explanation
Since this reaction absorbs heat, it is endothermic.
The energy absorbed per mole CO is 2.80 kJ and this reaction is already balanced. q= 2.80 kJ
Hope this helps:)
Answer:
Only dichloromethane will be present as bottom layer and other given solvents will be present as top layer in an aqueous extraction.
Explanation:
Whether the aqueous layer would be present on top or bottom, is decided by densities of the solvent.
Solvent which is less denser than water will be present as top layer in aqueous extraction and solvent which is more denser than water will be present as bottom layer.
Therefore,
a) Methanol is less dense than water, hence will be present as top layer in an aqueous layer.
b) Hexane is less dense than water, hence will be present as top layer in an aqueous layer.
c) Benzene is less dense than water, hence will be present as top layer in an aqueous extraction.
d) dichloromethane is more dense than water and hence will be present as bottom layer in aqueous extraction
e) diethyl ether is less dense and will be present as top layer in an aqueous layer.
So, only dichloromethane will be present as bottom layer and other given solvents will be present as top layer in an aqueous extraction.