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meriva
2 years ago
6

You are given 24.3 grams of Mg and combine it with 32.1 grams of Sulfur, what is the mass of MgS? *

Chemistry
1 answer:
koban [17]2 years ago
5 0

Answer:

ExplanatioFirst let us compute for the molar mass of Mg(OH)2.

molar mass = 24.3 + 2 (16) + 2(1.0)

molar mass = 58.3 g/mol

 

So the mass is then:

mass = 3.2 mol * (58.3 g/mol)

mass = 186.56 gramsn:

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A photon has a frequency of 2.68 x 10^6 HZ calculate it's energy
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150 ml of 0.1 m naoh is added to 200 ml of 0.1 m formic acid, and water is added to give a final volume of 1 l. what is the ph o
N76 [4]

Number of moles of NaOH = V(NaOH) * M(NaOH)= 0.150 L * 0.1 moles/L = 0.015 moles

Number of moles of formic acid, HCOOH = V(HCOOH) * M(HCOOH) = 0.200 L * 0.1 moles/L = 0.020 moles

Here, the limiting reagent is NaOH

The reaction is represented as:

HCOOH + NaOH ↔HCOONa + H2O

Moles of HCOONa formed = Moles of the limiting reagent, NaOH = 0.015 moles

Moles of HCOOH remaining = 0.020-0.015 = 0.005 moles

Total final volume is given as 1 L

Therefore: [HCOOH] = 0.005 moles/1 L = 0.005 M

[HCOONa] = 0.015/1 = 0.015 M

pKa of HCOOH = 3.74

As per Henderson-Hasselbalch equation

pH = pka + log[HCOONa]/[HCOOH] = 3.74+log[0.015/0.005] = 4.22

Therefore, pH of the final solution = 4.22


                       


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What is the pH of solution if the concentration of [H3O+] = 0.000558?
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