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2 years ago

You are given 24.3 grams of Mg and combine it with 32.1 grams of Sulfur, what is the mass of MgS? *

Chemistry

1 answer:

koban [17]2 years ago

5 0

Answer:

ExplanatioFirst let us compute for the molar mass of Mg(OH)2.

molar mass = 24.3 + 2 (16) + 2(1.0)

molar mass = 58.3 g/mol

So the mass is then:

mass = 3.2 mol * (58.3 g/mol)

mass = 186.56 gramsn:

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Mazyrski [523]

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Explanation:

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Substance is distributed in non uniform manner.
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3 years ago

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Answer:

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3 years ago

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Pani-rosa [81]

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2 years ago

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A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume

Kipish [7]

Answer:

Final pressure in (atm) (P1) = 6.642 atm

Explanation:

Given:

Initial volume of gas (V) = 12.5 L

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Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

$\frac{PV}{T} =\frac{P1V1}{T1} \\\\\frac{(784)(12.5)}{295} =\frac{(P1)(2.04)}{310}\\\\33.22 = \frac{(P1)(2.04)}{310}\\\\P1=5,048.18877$

⇒ Final pressure (P1) = 5,048.18877 torr

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