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Vadim26 [7]
3 years ago
7

Which group has different numbers of valence electrons

Chemistry
1 answer:
shusha [124]3 years ago
3 0

Answer:

where are the group?

Explanation:

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In an estuary, _____.
lapo4ka [179]

B; Seawater mixes with freshwater so the water has intermediate salinity

Explanation:

In an estuary, seawater mixes with freshwater so the water has intermediate salinity. Estuaries are usually located in transitional environments.

  • Estuary is the wide part of a river where it nears the sea.
  • This is called a transitional zone.
  • Water from continental rivers usually fresh are brought in close contact with ocean water that is salty.
  • The water here is said to be brackish as it is intermediate between salt and seawater.
  • Organisms living in such terrain must be be well adapted to changing salinity.

Learn more:

salinity and density brainly.com/question/10491444

#learnwithBrainly

6 0
2 years ago
Calculate the ph of the solution resulting by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh
Aliun [14]

Answer:

1.60.

Explanation:

  • The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
  • The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.

<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>

<em></em>

∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.

∵ pH = - log[H⁺]

<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>

5 0
3 years ago
How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN +
leonid [27]
The purpose of a chemical equation is to relate the amounts of reactants to the amounts of products based on the rate each is consumed. In this problem, one mole of sulfuric acid is consumed along with two moles of sodium cyanide to produce two moles of hydrocyanic acid and one mole of sodium sulfate. The relationship between sodium cyanide and sodium sulfate is 2:1, meaning that two moles of NaCN is required to produce one mole of sodium sulfate.

To produce 4.2 moles of sodium sulfate, two times this amount of NaCN is required. This means that you would need 8.4 moles of sodium cyanide.

Hope this helps!
4 0
3 years ago
Read 2 more answers
Helpppooo give answer thanks
DaniilM [7]

Answer:

625 mL

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 250 mL

Molarity of stock solution (M₁) = 5 M

Molarity of diluted solution (M₂) = 2 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

5 × 250 = 2 × V₂

1250 = 2 × V₂

Divide both side by 2

V₂ = 1250 / 2

V₂ = 625 mL

Therefore, the volume of the diluted solution is 625 mL.

8 0
2 years ago
Explain why a luminous flame of a Bunsen burner produces bright yellow light​
telo118 [61]

Answer:

because of the small soot particles

4 0
2 years ago
Read 2 more answers
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