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Ipatiy [6.2K]
3 years ago
12

A boy rolls a toy car across a floor with a velocity of 3.21 m/s. How long does it take the car to travel a distance of 4.50 m?

Physics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

Time taken for the car to travel a distance of 4.50 m = 1.40 seconds

Explanation:

velocity of toy car = 3.21 m/s

distance travelled by toy car = 4.50 m

Time = ?

Velocity = \frac{Distance}{Time} \\Time =\frac{Distance}{Velocity}

Time = \frac{4.50}{3.21} \\Time = 1.40s

Therefore, the time taken for the car to travel a distance of 4.50 m = 1.40 seconds

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Sultan throws a ball horizontally from his window, 12 m above the garden. It reaches the ground after
Kay [80]

Answer:

<h2>2.4</h2>

Explanation:

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8 0
3 years ago
49. A 6.1-kg bowling ball is liſted 2.1 m to a shell. Find
stealth61 [152]

Answer:

125.5J

Explanation:

Given parameters:

Mass of the bowling ball  = 6.1kg

Height of lifting  = 2.1m

Unknown:

Increase in the ball energy  = ?

Solution:

The ball has changed position by moving it from one point to another. So, it has acquired more potential energy.

 Potential energy  = mgh

     m is the mass

     g is the gravity  

     h is the height

Now insert the given parameters and solve;

       Potential energy  = 6.1 x 9.8 x 2.1  = 125.5J

5 0
3 years ago
Consider a 24.0 V storage battery that can transfer, over the course of its useful lifetime, a total charge equivalent to 340000
xeze [42]

Answer:

Explanation:

Given that,

Potential difference of battery is

V = 24V

Total charge battery can transferred

q = 340,000C

Work done by the battery?

Work done is given as

W = qV

Where q is charge in Columbs

V is potential difference in Volts

Then, W = qV

W = 340,000×24

W = 8,160,000 J

Work done by the battery over it's useful life time is 8,160,000J

5 0
3 years ago
4. A meter has a resistance of 100 Ω and gives a full scale deflection when it carries a current of 25 μA. (a) What resistor, Rx
frez [133]

Answer:

A=50mΩ

B≅50mΩ

Explanation:

A) To answer this question we have to use the Current Divider Rule. that rule says:

Ix=.\frac{Req}{Rx} *Itotal (1)

Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.

We now have a set of two resistor in parallel, so:

Req.=\frac{1}{\frac{1}{R1}+\frac{1}{R2}  } (2)

where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).

substituting and rearranging (2)

Req.=\frac{ 100*R1}{R1+100} (3)

Now substituting (3) in (1).

25*10^{-6} =\frac{\frac{ 100*R1}{R1+100}}{100} *50*10^{-3}

solving this, The value of R1 is: 50mΩ

This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.

Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ

If you substitude this values on (2) Req. will be 49.97 mΩ.

7 0
3 years ago
(I) A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the la
xxMikexx [17]

Answer:

425 m

Explanation:

From the question,

v = 2x/t.................... Equation 1

Where v = speed of sound in air, x = Length of the lake, t = time.

make x the subject of the equation

x = vt/2............... Equation 2

Given: t = 2.5 s

Constant: v = 340 m/s.

Substitute these values into equation 2

x = 340(2.5)/2

x = 425 m.

Hence the length of the lake is 425 m

4 0
4 years ago
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