((sinA.cosB+cosA.sinB)^2)+(cosA.cosB-sinA.sinB)^2=1
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The rate at which the water was drained from the tank is 6 gallons of water per minute (option A)
To know the speed at which the tank was drained, we must carry out the following operations:
Taking into account the information provided by the table we establish how much water has been drained from the tank in 20 minutes.
450 gallons - 330 gallons = 120 gallons.
Subsequently, we must divide the amount of water (120 gallons) that was drained by the time it was drained (20 minutes).
120 gallons ÷ 20 minutes = 6 gallons / minute.
According to the above, we can establish that the bath drain rate is 6 gallons / minute (option A).
Note: This question is incomplete because there is some missing information. Here is the complete information:
What is the rate at which the water was drained from the tank?
- 6 gallons of water per minute.
- 11 gallons of water per minute.
- 45 gallons of water per minute.
- 120 gallons of water per minute.
Learn more about linear equation in: brainly.com/question/11897796
Answer: because √-1 complex number ; and -√1 real number
Step-by-step explanation:
because √-1 complex number ; and -√1 real number or