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Ierofanga [76]
3 years ago
6

((sinA.cosB+cosA.sinB)^2)+(cosA.cosB-sinA.sinB)^2=1​

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

See below.

Step-by-step explanation:

((sinA.cosB+cosA.sinB)^2)+(cosA.cosB-sinA.sinB)^2=1​

The 2 halves of this expression are the identities for [sin(A + B)]^2 and

[(cos (A + B)] ^2 respectively , therefore:

((sinA.cosB+cosA.sinB)^2)+(cosA.cosB-sinA.sinB)^2 =  [sin(A + B)]^2 +

[(cos (A + B)] ^2

Using the identity sin^2Ф + cos^2Ф = 1  we see that if we put Ф = (A + B) we have

 [sin(A + B)]^2 + [(cos (A + B)] ^2 = 1  so the identity

((sinA.cosB+cosA.sinB)^2)+(cosA.cosB-sinA.sinB)^2 = 1  must be true also.

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Answer:

Axis is a vertical line at x = 2

Vertex is (2, -1)

y-intercept is (0, 3)

Solutions are x = 1 and x = 3

Step-by-step explanation:

To draw the graph of the quadratic equation you must find at least 5 points lie on the graph by choose values of x and find their values of y

Let us do that

Use x = -1, 0, 1, 2, 3, 4, 5

∵ y = x² - 4x + 3

∵ x = -1

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→ Plot point (-1, 8)

∵ x = 0

∴ y = (0)² - 4(0) + 3 = 0 + 0 + 3 = 3

→ Plot point (0, 3)

∵ x = 1

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→ Plot point (1, 0)

∵ x = 2

∴ y = (2)² - 4(2) + 3 = 4 - 8 + 3 = -1

→ Plot point (2, -1)

∵ x = 3

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→ Plot point (3, 0)

∵ x = 4

∴ y = (4)² - 4(4) + 3 = 16 - 16 + 3 = 3

→ Plot point (4, 3)

∵ x = 5

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→ Plot point (5, 8)

→ Join all the points to form the parabola

From the graph

∵ The axis of symmetry is the vertical line passes through the vertex point

∵ x-coordinate of the vertex point is 2

∴ Axis is a vertical line at x = 2

∵ The coordinates of the vertex point of the parabola are (2, -1)

∴ Vertex is (2, -1)

∵ The parabola intersects the y-axis at point (0, 3)

∴ y-intercept is (0, 3)

∵ x² - 4x + 3 = 0

∵ The solutions of the equation are the values of x at y = 0

→ That means the intersection points of the parabola and the x-axis

∵ The parabola intersects the x-axis at points (1, 0) and (3, 0)

∴ Solutions are x = 1 and x = 3

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Answer:

See explanation

Step-by-step explanation:

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